4/20 is 0.20, which is equivalent to 20%.
Remember that 1.0=100%, 0.5=50%, 0.2=20%, 0.05=5%, and so on.
Answer:
Answer is 0.5
Step-by-step explanation:
The text implies that the number of traffic accidents determines the number of ambulances required on the road. Hence, 1 traffic accident requires 1 ambulance.
The time slot and time of day remain same in both the text and the question.
The average or mean number of accidents is 1.1
QUESTION: What then is the probability that there is need for exactly 2 ambulances on that road and in that time frame?
In other words, what is the probability that there'll be 2 accidents on that road and in that time frame?
Since the mean number of accidents is 1.1, 2 is above the mean.
Probability of 1.1 accidents is 1, since that's the mean (expected value).
Probability of 2 accidents is 1/2 which is = 0.5
120 - 3/4y=60
lowest common multiple=4y
480y-3=240y
480y-240y=3
240y=3
y=3/240
y=1/80
Answer: y=1/80
Answer:
y= -3x +10
the y-intercept is at 10 and then go 3 down one to the right
Step-by-step explanation:
A.) $15 would seem like it would be right
