Question

Suppose you have an isosceles triangle with a 90° angleIf the congruent sides each measure 9 feet, what is the length of the side across from the right angle?

Answer 1

Answer:

$9\sqrt{2}$ feet

Step-by-step explanation:

Consider the attached figure.

An isosceles triangle is a triangle in which two sides are equal.

$AB=BC=9$ feet

According to Pythagoras theorem,

square of hypotenuse is equal to sum of squares of other two sides.

$AC^2=AB^2+BC^2\\AC^2=9^2+9^2\\AC^2=81+81\\AC^2=162\\AC=\sqrt{162}$

$AC=9\sqrt{2}$ feet