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Alexandra [31]
3 years ago
14

Suppose you have an isosceles triangle with a 90° angleIf the congruent sides each measure 9 feet, what is the length of the sid

e across from the right angle?
Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0

Answer:

9\sqrt{2} feet

Step-by-step explanation:

Consider the attached figure.

An isosceles triangle is a triangle in which two sides are equal.

AB=BC=9 feet

According to Pythagoras theorem,

square of hypotenuse is equal to sum of squares of other two sides.

AC^2=AB^2+BC^2\\AC^2=9^2+9^2\\AC^2=81+81\\AC^2=162\\AC=\sqrt{162}

AC=9\sqrt{2} feet

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What is the domain of the function s=-4r^2 if the range is s <_ 0
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Answer:

r≤0

Step-by-step explanation:

if the range is s≤0, (that means the value of s is all negative integers &0) to find the domain we have to replace that some negative integers &0.

we can replace some values of s as the following

s=‒4(0)^2 s=‒4(‒1)^2

=‒4(0) =‒4(1)

=0 =‒4

s=‒4(‒2)^2 s=‒4(‒3)^2

=‒4(4) =‒4(9)

=‒16 =‒36

so we can understand easly that the domain is negative integer&0,it can't be positive because the square of any integer is positive.

therefore the answer is r≤0

i think &i hope it is clear.

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