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Molodets [167]
3 years ago
8

Simplify the following algebraic expression 5x– 4у + 3y+8y – 7х​

Mathematics
1 answer:
Margarita [4]3 years ago
4 0

Answer:

<h2><em><u>-2x</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>7y</u></em></h2>

Step-by-step explanation:

<em><u>Given</u></em><em><u>, </u></em>

5x– 4у + 3y+8y – 7х

<em>[Bringing like terms together]</em>

= 5x - 7x - 4y + 3y + 8y

<em>[</em><em>Adding</em><em> </em><em>and</em><em> </em><em>subtracting</em><em> </em><em>the</em><em> </em><em>like</em><em> </em><em>terms</em><em>]</em>

= <em><u>- 2x + 7y (Ans)</u></em>

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- (t + 3) - 10 = -6.5
USPshnik [31]

Answer:  =  − 6 . 5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
HELP! I don’t know what to do for #4. well i don’t know what to put for another equation. i Dont need help solving i just need h
OLga [1]

Let s = #small notebooks

Let L = #large notebooks

 

We Can set up two equations from the info given.

 

s + L = 6           bought 6 notebooks total

8s + 10L = 56    spent $56

 

Solve equation 1 for one variable.

L = 6-s

 

Plug 6-s in equation 2 in place of L

and solve for s

 

8s + 10(6-s) = 56

8s + 60 - 10s = 56

-2s + 60 = 56

-2s = -4

s = (-4)/(-2)

s = 2

 We know s+L = 6 and s=2

2+L = 6

L = 4

 4 large notebooks and 2 small notebooks

were purchased

3 0
3 years ago
Bill spends two days driving from Point A to Point B . On the first day, he drove 2 hours longer and at an average speed 5 miles
Rainbow [258]

Answer:

His average speed on the second day is 35 miles per hour.

Step-by-step explanation:

Consider the provided information.

On first day, he drove 2 hours longer than he drove on second day.

Let x = Number of hours he drove on second day.

Then x + 2 = Number of hours he drove on first day.

It is given that he drove a total of 18 hours.

Therefore,

x + (x + 2) = 18

2x + 2= 18

x=8

He drove 8 hours on second day.

x + 2 = 8+2=10

He drove 10 hours on first day.

Let y = speed driven on second day.

y + 5 = speed driven on first day.

As we know: Distance = speed × time

On first day he covers a distance of:

Distance = 10(y+5)

On second day he covers a distance of:

Distance = 8(y)

Total distance = Day 1 distance + Day 2 distance

10(y+5) + 8(y) = 680\\10y+50+8y=680\\18y=630\\y=35

Hence, his average speed on the second day is 35 miles per hour.

6 0
3 years ago
Please help me Solve for r: r/5 = 7
QveST [7]
Multiply both sides by 5
r = 35
7 0
3 years ago
P(A) = 7/20 P(B) = 7/20 P(A or B) = 49/80, P(A and B)= ?​
OverLord2011 [107]

Answer:

P(A and B) = 7/80

Step-by-step explanation:

The given values of the probabilities of the different events are;

P(A) = 7/20

P(B) = 7/20

P(A or B) = 49/80

P(A and B) = Required

We have by probability theory for any event;

P(A or B) = P(A) + P(B) - P(A and B)

Therefore;

P(A and B) = P(A) + P(B) - P(A or B)

Plugging in the values gives;

P(A and B) = 7/20 + 7/20 - 49/80 = 7/80

∴ P(A and B) = 7/80

8 0
3 years ago
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