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3 years ago

What greatest common factors go into 12

2 answers:

6 0

The greatest commons factors are for 12 is 1,2,3,4,6,12 because 2 × 6 = 12, or 4 × 3 = 12, or 1 × 12 = 12 hope that help!

mr Goodwill [35]3 years ago

3 0

Hi!

To find the answer, right all the number that are smaller than 12 (not negative), and see if they go into 12.

12/12 = 1

12/11 = nope

12/10 = nope

12/9 = nope

12/8 = nope

12/7 = nope

12/6 = 2

12/5 = nope

12/4 = 3

12/3 = 4

12/2 = 6

12/1 = 12

The answer is 1,2,3,4,6 and 12

Hope this helps! :)

-Peredhel

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A rectangular piece of paper with length 35 cm and a width 18 cm has two semicircles cut out of it as shown below

Eddi Din [679]

Answer:

375.66 cm²

Step-by-step explanation:

The two semicircles add to a full circle.

For the circle, d = 18 cm.

r = d/2 = 9 cm.

A = LW - πr²

A = (35 cm)(18 cm) - 3.14(9 cm)²

A = 375.66 cm²

3 0

3 years ago

Show work, can someone help me out having trouble with this problem

Over [174]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: f = \cfrac{9}{a}+7$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \:a = \cfrac{9}{f - 7}$

$\qquad \tt \rightarrow \:a(f - 7) = 9$

$\qquad \tt \rightarrow \:(f - 7) = \cfrac{9}{a}$

$\qquad \tt \rightarrow \:f = \cfrac{9}{a} + 7$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

7 0

2 years ago

An object is completely submerged in a liquid of density 0.65 grams per cubic centimeter at a depth of 3 meters. What is the tot

3241004551 [841]

The pressure due to the depth in a liquid can be calculated as:
P = ρgh; ρ is the density in kg/m³, g is the acceleration due to gravity in m/s² and h is the depth in the fluid.
ρ = 0.65 g/cm³ = 650 kg/m³
P = 650 x 9.81 x 3
= 19100 Pascals
Pressure in atm = 19100/101325 atm
= 0.188 atm

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3 years ago

What is the product?<br> (X^4)(3x^3-2)(4x^2 +5x)?

RideAnS [48]

This is what I got sorry if it’s incorrect I tried..