Question

What are the potential solutions of In(x2 - 25) = 0?

Answer 1

Answer:

$x=\pm\sqrt{26}$

Step-by-step explanation:

$ln(x^2-25)=0$

$e^{ln(x^2-25)}=e^0$

$x^2-25=1$

$x^2=26$

$x=\pm\sqrt{26}$