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3 years ago

What are the potential solutions of In(x2 - 25) = 0?

Mathematics

1 answer:

Paha777 [63]3 years ago

7 0

Answer:

$x=\pm\sqrt{26}$

Step-by-step explanation:

$ln(x^2-25)=0$

$e^{ln(x^2-25)}=e^0$

$x^2-25=1$

$x^2=26$

$x=\pm\sqrt{26}$

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