Answer:
Step-by-step explanation:
REcall the following definition of induced operation.
Let * be a binary operation over a set S and H a subset of S. If for every a,b elements in H it happens that a*b is also in H, then the binary operation that is obtained by restricting * to H is called the induced operation.
So, according to this definition, we must show that given two matrices of the specific subset, the product is also in the subset.
For this problem, recall this property of the determinant. Given A,B matrices in Mn(R) then det(AB) = det(A)*det(B).
Case SL2(R):
Let A,B matrices in SL2(R). Then, det(A) and det(B) is different from zero. So
.
So AB is also in SL2(R).
Case GL2(R):
Let A,B matrices in GL2(R). Then, det(A)= det(B)=1 is different from zero. So
.
So AB is also in GL2(R).
With these, we have proved that the matrix multiplication over SL2(R) and GL2(R) is an induced operation from the matrix multiplication over M2(R).
4x-5y=-15
That’s the answer your welcome
Answer:
Explanation:
Hello,
In this case, based on the given rewritten reaction:
The stoichiometry leads to the following theoretical moles of oxygen:
As sodium and hydrogen as a 2 to 1 molar relationship.
Step-by-step explanation:
By flipping the fraction of -3/7, you will get the fraction of -7/3 or - 2 1/3.
Therefore, the reciprocal of -3/7 is - 2 1/3.
Hope this helps!
Find area of square: 7^2 = 49
Find radius of circle: 7/2=3.5
find area of circle: 3.5^2*3.14=38.465
Remove area of circle from area of square:
49-38.465=10.535 cm^2
Answer A is the correct one :)