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Over [174]
3 years ago
13

In the theory of learning, the rate at which a subject is memorized is assumed to be proportional to the amount that is left to

be memorized. Suppose M denotes the total amount of a subject to be memorized and A(t) is the amount memorized in time t > 0. Determine a differential equation for the amount A(t). (Assume the constant of proportionality is k > 0. Use A for A(t).)
Mathematics
1 answer:
fiasKO [112]3 years ago
4 0

Step-by-step explanation:

From the statement:

M: is total to be memorized

A(t): the amount memorized.

The key issue is translate this statement as equation "rate at which a subject is memorized is assumed to be proportional to the amount that is left to be memorized"

memorizing rate is \frac{dA(t)}{dt}.

the amount that is left to be memorized can be expressed as the total minus the amount memorized, that is M-A(t).

So we can write

\frac{dA(t)}{dt}=k(M-A(t))

And that would be the differential equation for A(t).

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Thời gian để sản xuất một sản phẩm loại A là một BNN tuân theo luật phân phối chuẩn với các tham số m = 15 và s= 2 (đơn vị là ph
ser-zykov [4K]

Answer:

A= -u²n²t²s²arme²

Step-by-step explanation:

Evaluate m, then set it equal to 15.

=15

Evaluate s, the set it equal to 2.

=2

Simplify unitsareminutes.

−u²n²t²s²arme²

List all the solutions.

BN•N=BN²

m=15 ==15

s=2 2==2

8 0
2 years ago
In the diagram below segment DEF is shown(since all three letters are shown, they are collinear). If DE=3x+2, EF= x+5, and DF= 2
amm1812

The value of x is 4.

By Geometry, we know that line segment DF = DE + EF, which is equivalent to:

DF = 3\cdot x + 2 + x + 5

DF = 4\cdot x + 7 (1)

Now we solve algebraically the resulting expression.

If we know that DF = 23, then we solve the equation for x:

4\cdot x + 7 = 23

4\cdot x = 16

x = 4

The value of x is 4.

We kindly invite to see this question on line segments: brainly.com/question/23297288

6 0
2 years ago
Write as a product: ax^2+ay^2–bx^2–by^2+b–a
Vesna [10]

Answer:

\large\boxed{ax^2+ay^2-bx^2-by^2+b-a=(a-b)(x^2+y^2-1)}

Step-by-step explanation:

ax^2+ay^2-bx^2-by^2+b-a\\\\=(ax^2-bx^2)+(ay^2-by^2)+(b-a)\qquad\text{use the distributive property}\\\\=x^2(a-b)+y^2(a-b)-1(a-b)\\\\=(a-b)(x^2+y^2-1)

4 0
3 years ago
What type of polynomial is: 3x^4 - 2x^3 - 2
butalik [34]

This polynomial has only 3 terms, so it is a trinomial. <em>Hope it helps!</em>

3 0
1 year ago
Thrice the product of two and "Y".
love history [14]

Answer:

6Y

Step-by-step explanation:

We need to solve the statement ' Thrice the product of two and "Y" '.

Thrice means 3 times and product means multiply. It means we have to multiply 3,2 and Y.

Let the result is R. It can be calculated as follows :

R=3\times 2\times Y

We know that, 3×2 = 6

So,

R=6Y

Hence, Thrice the product of two and "Y" is 6Y.

6 0
3 years ago
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