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Over [174]
3 years ago
13

In the theory of learning, the rate at which a subject is memorized is assumed to be proportional to the amount that is left to

be memorized. Suppose M denotes the total amount of a subject to be memorized and A(t) is the amount memorized in time t > 0. Determine a differential equation for the amount A(t). (Assume the constant of proportionality is k > 0. Use A for A(t).)
Mathematics
1 answer:
fiasKO [112]3 years ago
4 0

Step-by-step explanation:

From the statement:

M: is total to be memorized

A(t): the amount memorized.

The key issue is translate this statement as equation "rate at which a subject is memorized is assumed to be proportional to the amount that is left to be memorized"

memorizing rate is \frac{dA(t)}{dt}.

the amount that is left to be memorized can be expressed as the total minus the amount memorized, that is M-A(t).

So we can write

\frac{dA(t)}{dt}=k(M-A(t))

And that would be the differential equation for A(t).

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The answer is 2600 or 3000 but tri the firstoe


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4 years ago
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Wha is the area of this
Korvikt [17]

Octagon, stop sign.

Eight isoscles triangles.   It looks like we're told the side is 9.9 and the height to the side (also called the apothem) is 12.

So each isosceles triangle has area  (1/2)(9.9)(12) and we have eight of them,

area = 8(1/2)(9.9)(12) = 475.2

Answer: 475.2

Usually we wouldn't be told 9.9 -- this is the baby version.  We know each of those isoscles triangles has unique angle 360/8=45 degrees, so the apothem and half the side of the octagon are a right triangle with acute angle 22.5 degrees.

The area of the right triangle with long leg 12, short leg x,

tan 22.5 = x/12 or

x = 12 tan 22.5

Twice that is what we're told is 9.9; let's check:

2x = 24 tan 22.5 = 9.941125496954282

The area of the little right triangle is

(1/2) 12 × 12 tan 22.5

and there are 16 of these

16 (1/2) 12 × 12 tan 22.5 ≈ 477.174

6 0
3 years ago
Confused on the steps and I need help
lions [1.4K]

9514 1404 393

Answer:

  3) y = -1

  5) x = -14

Step-by-step explanation:

The first step is to recognize that the equation describes a vertical line in problem 3 and a horizontal line in problem 5. The perpendicular to a vertical line is a horizontal line, and vice versa.

__

3. To make the desired horizontal line go through the point (-8, -1) the y-value of the line must match that of the point:

  y = -1

__

5. To make the desired vertical line go through the point (-14, 81), the x-value of the line must match that of the point:

  x = -14

8 0
3 years ago
Question 1: Four expressions are shown below:
vekshin1

Answers;

Question 1 answer: The first and last option.

Question 1 explanation: 2(4x + 2) is 4x = 12 = 2 = 14 x 2 = 28 and 8x + 4 is 8 x 4 = 32 + 4 = 36 which is 8 more than 28 then, 3x = 9 + 2 + 3 x 2 = 28.

2(4x + 2) = 28 and 8x + 4 equals 36 which is 8 more and they're both equivalent to 2(3x + 2 + x) because 2(3x = 2 = x) equals 28.

6 0
2 years ago
H(x)= 9/x( x^2-49)<br> Determine the domain of the function
Norma-Jean [14]

Answer: The domain of the function h(x) = \frac{9}{x(x^2-49)} is:

Interval Notation: (-∞ , -7) ∪ (-7 , 0) ∪ (0 , 7) ∪ (7, ∞)

Set-Builder Notation: { x | x ≠ 0 , 7 , -7 }

All real numbers besides 0, 7, and -7.

Step-by-step explanation:

In order to find the domain of your rational function, we need to simplify it:

h(x) = \frac{9}{x(x^2-49)} = \frac{9}{(x)(x+7)(x-7)}

Remember, most of the time, the domain of a rational function consists of all real numbers besides zero.

To find the domain, we equal the equations in the denominator to zero.

x=0

x+7=0 --> x=-7

x-7=0 --> x=7

So all real numbers except for 0, -7, and 7 are in the domain of this rational function.

8 0
3 years ago
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