Answer:
we conclude that the total number of perfect odd squares between 5 and 211 will be: 6
Step-by-step explanation:
Let us check by taking squares
As taking 14² = 256 would exceed 211, and 1² = 1 is smaller than 5.
Therefore, we conclude that the total number of perfect odd squares between 5 and 211 will be: 6
Answer:
second option
Step-by-step explanation:
Given
f(x) = - + 9 - 18x³
To find the zeros let f(x) = 0, that is
- + 9 - 18x³ = 0 ( multiply through by - 1 )
- 9 + 18x³ = 0 ← factor out x³ from each term
x³ (x² - 9x + 18) = 0 ← in standard form
x³(x - 3)(x - 6) = 0 ← in factored form
Equate each factor to zero and solve for x
x³ = 0 ⇒ x = 0 with multiplicity 3
x - 3 = 0 ⇒ x = 3 with multiplicity 1
x - 6 = 0 ⇒ x = 6 with multiplicity 1
Answer:
C: 583
Step-by-step explanation:
5(100)+8(10)+3(1)
500+80+3= 583
Hope this helps! :)
The value of the annuity would be $3512.58
Answer:
400 800 1200 1600 2000 is anwser