Question

What is the value of for x = 2 and y = –4?

Answer 1

Remember
x^-m=1/(x^m)



x=2
y=-4
$\frac{1}{(2^{-2})(x^{-3})(y^{5})}$

$\frac{1}{(2^{-2})((2)^{-3})((-4)^{5})}$

$\frac{1}{(1/(2^{2}))(1/(2^{3})(-1024)}$

$\frac{1}{(1/(4))(1/(8)(-1024)}$

$\frac{1}{(1/(32))(-1024)}$

$\frac{1}{-1024/(32)}$

-1/32 is result

Answer 2

Plug the number in
1/(2)^-2(2)^-3(-4)^5
change the negative exponents and it becomes
4(8)/-1024
32/-1024
-1/32