The fare of $(20 - 2.5) = $17.5 will maximize the total fare.
<h3>What is Differentiation?</h3>
Differentiation means the rate of change of one quantity with respect to another. The speed is calculated as the rate of change of distance with respect to time.
Here, The operator for a round-trip fare of $20, carries an average of 500 people per day.
It is estimated that 20 fewer people will take the trip, for each $1 increase in fare.
for $x increase in fare, 20x less people will take the trip and at that time the total fare F is given by
f(x) =(20 + x)(500 - 20x)
f (x) = 10000 + 100x - 20x²
For f(x) to be maximum, the condition is dy/dx = 0
100 - 40x = 0
⇒ x = 2.5
Thus, the fare of $(20 - 2.5) = $17.5 will maximize the total fare.
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Answer:
We can use slope intercept form to get the points needed. Y= -7+1/3x The points are (0,-7) and (3,-6)
Step-by-step explanation:
Subtract 2x from the left side and place it over to the right side with the 42. Now we have -6y= 42-2x. From here we divide by -6 and we get y= -7+1/3x. We know that are slope is 1/3 which the one is the rise and the 3 is the run. We also know that our y intercept is -7. We plot the points at (0,-7) and (3,-6)
Answer:
He had 0.8 liters to start with...
Step-by-step explanation:
0.44 is 55% of what? (what = x)
Equation: Y = P% * X
X = Y/P%
X = 0.44/55%
55% = 0.55
X = 0.44/0.55
X = 0.8
The profit does the company make from producing and selling four soccer nets is $109, the correct option is C.
<h3>
What is profit?</h3>
Profit is a financial benefit that is realized when the amount of revenue gained from a business activity.
Given
|Soccer nets per day | Total Cost | Total Revenue |
| 1 | 7$ | $30 |
| 2 | 9$ | $60 |
| 3 | 10$ | $90 |
| 4 | 11$ | $120 |
| 5 | 13$ | $150 |
The total cost in the four soccer = $11
The total revenue in the four soccer = $120
The profit does the company make from producing and selling four soccer nets is;

Hence, the profit does the company make from producing and selling four soccer nets is $109.
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Answer:
AC is equal to BA and BC is equal to CB