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fomenos
3 years ago
13

Determnine if each table shown below represents a function or not.

Mathematics
1 answer:
Kipish [7]3 years ago
6 0

                                                 Table 1

Input (x)               1            3           5            5              9

Output (y)             7           16          19          20           28

We know that a function is a relation where each input or x-value of the X set has a unique y-value or output of the Y set.

In other words, we can not have duplicated inputs as there should be only 1 output for each input.

From Table 1, it is clear that:

  • Each input or x-value of the X set has a unique y-value or output of the Y set.
  • There is no duplicated input (repeated x value).

Therefore, Table 1 represents a function.

                                                Table 2

Input (x)               0.5          7           7            12            15

Output (y)             7           15          10          23           30

 

We already know that a function is a relation where each input or x-value of the X set has a unique y-value or output of the Y set.

In other words, we can not have duplicated inputs as there should be only 1 output for each input.

From Table 2, it is clear that:

  • There is a duplicated input (repeated x value) i.e. x = 7 appears twice. And we can not have repeated input values.

As the input x = 7 is repeated multiple times, thus, the given table 2 does not represent a function.

Therefore,  Table 2 does not represent a function.

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1/4 (x + 12) = 5?<br> Simplify (distribute) and rewrite your expression <br> Solve for X
ladessa [460]

Answer: x = 8

Step-by-step explanation: 1/4(x+12)=5 is the same as 1/4x + 3 = 5. 1/4 of 8 is 2. 2+3=5.

5 0
3 years ago
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Andrew [12]
The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}
Since x^{a}* x^{b}  =x^{a+b}, then x^{9}= x^{3}* x^{6}

Back to our expression:
4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+  5y ^{6}*1=5 y^{6} (4y ^{3} +1)
The greatest common factor is thus 5 y^{6}


Q2. The answer is <span>D. 12xy^2
</span>
12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}
We will use the rule  x^{a}* x^{b} =x^{a+b} to factorise the exponents:
12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)
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3 0
3 years ago
PLEASE HELP ME I DONT UNDERSTAND.
Bingel [31]

width = 7cm

Length= 41cm

width=x

length=3x+20

96=3x+20+3x+20+x+x

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5 0
3 years ago
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Which sets of ordered pairs represent functions from A to B? (Select all that apply.) A = {a, b, c} and B = {3, 4, 5, 6}
sesenic [268]

Answer:

See Explanation

Step-by-step explanation:

<em>The question has mission options; However, the question is still solvable.</em>

Given

A = \{a,b,c\}

B = \{3,4,5,6\}

Required

Determine possible ordered pairs of A to B

A function is of the form (x,y)

Let A be the range of the function and B, the domain

Let (x,y) be a function of A to B, where x represents any of the values in A sets and y represents any of the values in B

A ordered pair can only be regarded as a function if and only if it has unique y-values

Hence, a possible ordered pair is:

(A,B) = \{(a,3),(b,4),(c,5)\}

Another possible ordered pair is

(A,B) = \{(a,4),(b,5),(c,6)\}

<em>Note that there as as many as possible ordered pair as long as the y-values are unique</em>

5 0
3 years ago
Please answer see the image below
fredd [130]

Answer:

<h2>64.8</h2><h2></h2>

Step-by-step explanation:

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                = (11 x 5) + (1/2 * π * 2.5²)

                = 55 + 9.8

                = 64.8 sq. units

5 0
3 years ago
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