So I drew a number line , & I placed point e at 1 1/4 . The correct answer will be B . It couldn't be A because if point e was 1/4 to the left of 1 , point e will be located at 3/4 . But because it ask to put point e at 1 1/4 , you would look for 1 & just move up 1/4 .
Answer:
i dont know what a number bound is but
16*9 - 5*9 = 144 - 45 = 99
Hope this helped and brainliest please
During its first bake sale, the poetry club made $79.35. If we round up to $80, this will make it easier to estimate how much they will make if they have 4 more bake sales (5 altogether). Next, we should use multiplication to determine how much money they will earn altogether after 5 bake sales. Five times $80 equals $400. Leslie accidentally multiplies by 50 because she moves the decimal one place too far.
<h3>Further Explanation</h3>
Estimation
Estimation is when you use an approximate calculation to make a prediction. It is important here to note that an estimation is different than guess. In both instances, one should use whatever knowledge is at their disposal; however, an estimation usually uses rounding and actual calculations.
Rounding
When making an estimation, rounding is an effective tool to use. Often numbers are rounded to the nearest whole number or place value. This can make it easier to do a quick calculation. In the word problem, the nearest whole number to 79.35 is 80. This makes it easier to multiply the dollar amount because there are fewer numbers to multiply.
<h3>Answer Details</h3>
Subject: Math
Level: middle school
Topic: Estimations
<h3>Keywords</h3>
estimation, rounding, multiplication
<h3>Learn More</h3>
Estimating with percents: brainly.com/question/3510011
Estimate: brainly.com/question/107747
Answer:
Hello!!
Mr. Ophaug earns $100 every 2 hours for tutoring kids in math after school. He is willing to tutor up to 6 hours each week. Create a table of values for this scenario and find the rate of change.
time (h) money earned
2 $100
3 $150
4 $200
5 $250
6 $300
Hope this helps!!
2logx = log64
2logx = log(2)⁶
2logx = 6.log(2)
logx = 3log (2)
logx=log(2)³ ===> x = 2³ & x = 8
