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Marrrta [24]
3 years ago
9

Which two values are greater than 3/5

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
5 0

Answer:

1 and 4/5

Step-by-step explanation:

4/5 is greater then 3/5 and 5/5=1 whole which is greater than 3/5, 4/5 and 1 is greater than 3/5 and 1 1/5, 1 2/5 so on and so on it could go forever but 4/5, and 1 is the only ones that our after 3/5 so those are the two greatest ones in this quistion. Hope this helps

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What is the property of 6x=72?
Andreyy89

Addition and multiplication are commutative property so that mean no.

In this case, you have to do division.

Your answer is 6x = 72

x = 12

Hope this helps :)

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3 years ago
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2,4,6,8...<br> What is the 32nd term of this sequence?
Elza [17]

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Step-by-step explanation:

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2 years ago
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Findℒ{f(t)}by first using a trigonometric identity. (Write your answer as a function of s.)f(t) = 12 cost −π6
allsm [11]

Answer:

L(f(t)) = \dfrac{6}{S^2+1} [\sqrt{3} \ S +1 ]

Step-by-step explanation:

Given that:

f(t)  = 12 cos (t- \dfrac{\pi}{6})

recall that:

cos (A-B) = cos AcosB + sin A sin B

∴

f(t) = 12 [cos\  t \  cos \dfrac{\pi}{6}+ sin \ t  \ sin \dfrac{\pi}{6}]

f(t) = 12 [cos \  t \ \dfrac{3}{2}+ sin  \ t  \ sin \dfrac{1}{2}]

f(t) = 6 \sqrt{3} \ cos \ (t) + 6 \ sin \ (t)

L(f(t)) = L ( 6 \sqrt{3} \ cos \ (t) + 6 \ sin \ (t) ]

L(f(t)) = 6 \sqrt{3} \ L [cos \ (t) ] + 6\ L [ sin \ (t) ]

L(f(t)) = 6 \sqrt{3}  \dfrac{S}{S^2 + 1^2}+ 6 \dfrac{1}{S^2 +1^2}

L(f(t)) = \dfrac{6 \sqrt{3} +6 }{S^2+1}

L(f(t)) = \dfrac{6( \sqrt{3} \ S +1 }{S^2+1}

L(f(t)) = \dfrac{6}{S^2+1} [\sqrt{3} \ S +1 ]

7 0
3 years ago
One edge of a cube measures 4.6 meters. What is the volume of the cube? Enter your answer, as a decimal, in the box.
ra1l [238]
Volume = l x w x h
4.6 x 4.6 x 4.6=97.336
7 0
3 years ago
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