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Damm [24]
3 years ago
5

If two sides of an isosceles triangle each measure 1/4 inch and the third side measures 3/8 inch what is the perimeter of the tr

iangle
Mathematics
2 answers:
patriot [66]3 years ago
7 0
0.875 inches is the correct answer.
alukav5142 [94]3 years ago
4 0
Its perimeter would equal 7/8 inch (1/4+1/4=2/4=4/8+3/8=7/8)
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Help plz will mark brainliest :)​
avanturin [10]

Answer:

c

Step-by-step explanation:

subtract b from both sides

divide by x

5 0
2 years ago
What are the solutions to the equation 2(x-3)^2=54 ?
erastova [34]

Answer:

      x =(6-√108)/2=3-3√ 3 = -2.196

 x =(6+√108)/2=3+3√ 3 = 8.196

Step-by-step explanation:

Step  1  :

Equation at the end of step  1  :

2 • (x - 3)2 - 54 = 0

Step  2  :

 2.1    Evaluate :  (x-3)2   =  x2-6x+9 

Step  3  :

Pulling out like terms :

 3.1     Pull out like factors :

   2x2 - 12x - 36  =   2 • (x2 - 6x - 18) 

Adding  9  has completed the left hand side into a perfect square :

   x2-6x+9  =

   (x-3) • (x-3)  =

  (x-3)2  (x-3)1 =

   x-3

Now, applying the Square Root Principle to  Eq. #4.3.1  we get:

   x-3 = √ 27

Add  3  to both sides to obtain:

   x = 3 + √ 27

Since a square root has two values, one positive and the other negative

   x2 - 6x - 18 = 0

   has two solutions:

  x = 3 + √ 27

   or

  x = 3 - √ 27

Solve Quadratic Equation using the Quadratic Formula

 4.4     Solving    x2-6x-18 = 0 by the Quadratic Formula .

 According to the Quadratic Formula,  x  , the solution for   Ax2+Bx+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :

                                     

            - B  ±  √ B2-4AC

  x =   ————————

                      2A

  In our case,  A   =     1

                      B   =    -6

                      C   =  -18

Accordingly,  B2  -  4AC   =

                     36 - (-72) =

                     108

Applying the quadratic formula :

               6 ± √ 108

   x  =    —————

                    2

Can  √ 108 be simplified ?

Yes!   The prime factorization of  108   is

   2•2•3•3•3 

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 108   =  √ 2•2•3•3•3   =2•3•√ 3   =

                ±  6 • √ 3

  √ 3   , rounded to 4 decimal digits, is   1.7321

 So now we are looking at:

           x  =  ( 6 ± 6 •  1.732 ) / 2

Two real solutions:

 x =(6+√108)/2=3+3√ 3 = 8.196

or:

 x =(6-√108)/2=3-3√ 3 = -2.196

7 0
2 years ago
What are three solutions to the equation -8y=-3x+16?
andreyandreev [35.5K]
The answer is <span>Slope = 0.750/2.000 = 0.375 
x-intercept = 16/3 = 5.33333<span> 
y-intercept = 16/-8 = 2/-1 = -2.00000 hope this helps</span></span>
8 0
3 years ago
Miranda enlarged a picture twice as shown below, each time using a scale factor of 3.
lyudmila [28]

Answer:

The area of the second enlargement is 1,944 square inches

The area of the second enlargement is (3 squared) squared times the original area.

The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor

Step-by-step explanation:

<u><em>Verify each statement</em></u>

1) The area of the first enlargement is 72 square inches.

The statement is false

Because

we know that

The original dimensions of the rectangle are

length 6 inches and width 4 inches

so

First enlargement

Multiply the original dimensions by a scale factor of 3

Length: 6(3)=18\ inches\\Width: 4(3)=12\ inches

The area of the first enlargement is

18(12)=216\ in^2

2) The area of the second enlargement is 1,944 square inches

The statement is true

Multiply the dimensions of the first enlargement by a scale factor of 3

Length: 18(3)=54\ inches\\Width: 12(3)=36\ inches

The area of the second enlargement is

54(36)=1,944\ in^2

3) The area of the second enlargement is (3 squared) squared times the original area.

The statement is true

Because

The original area is 24 square inches

[(3^2)]^2(24)=1,944\ in^2

4) The area of the second enlargement is 3 times the area of the first enlargement

The statement is false

Because

3(216)=648\ in^2

so

648\ in^2 \neq 1,944\ in^2

5) The ratio of the area of the first enlargement to the area of the original equals the square of the scale factor

The statement is true

Because

The square of the scale factor is 3^2=9

and the ratio is equal to

\frac{216}{24}=9

8 0
2 years ago
Read 2 more answers
In the rectangle below ac=48 units what is de
r-ruslan [8.4K]

Answer:

24

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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