Pls!!

The specification for the pull strength of a wire that connects an integrated circuit to its frame is 10 g or more. In a sample

Wittaler [7]

Answer:

The 95% confidence interval for the difference is (-0.1888, 0.0202).

Step-by-step explanation:

Difference between proportions:

The distribution of the difference between two proportions has mean of the difference between these proportions and standard deviation is the square root of the sum of the variances. So

In a sample of 86 units made with gold wire, 68 met the specification

This means that:

$pX = \frac{68}{86} = 0.7907$

$sX = \sqrt{\frac{0.7907*0.2093}{86}} = 0.0439$

In a sample of 120 units made with aluminum wire, 105 met the specification.

This means that:

$pY = \frac{105}{120} = 0.875$

$sY = \sqrt{\frac{0.875*0.125}{120}} = 0.0302$

Difference:

$p = pX - pY = 0.7907 - 0.875 = -0.0843$

$s = \sqrt{sX^2 + sY^2} = \sqrt{0.0439^2+0.0302^2} = 0.0533$

Confidence interval:

$p \pm zs$

In which z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ , with $\alpha$ being 1 subtracted by the confidence level.

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Lower bound of the interval:

$p - zs = -0.0843 - 1.96*0.0533 = -0.1888$

Upper bound of the interval:

$p + zs = -0.0843 + 1.96*0.0533 = 0.0202$

The 95% confidence interval for the difference is (-0.1888, 0.0202).

6 0

3 years ago

What is the determinant of k =[ 6 8]

Sergeeva-Olga [200]

That would be 6 *3 - 8*0 = 18

Its D

5 0

3 years ago

Robert climbed 775 steps and 12 1/2 minutes. How many steps did he average per minute?

UNO [17]

Answer:

Since the question requires you to give the answer in terms of steps/minute, the first step would be to convert hours to minutes: 12.5 hours = 750 minutes. Next, if he took 775 steps in 750 minutes, how many would he take in 1 minute? This requires you to set up the question as a proportion: (775 steps/ 750 minutes) = (x steps/1 minute)

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

Find the 25th term of the arithmetic sequence whose common difference is d=5 and whose first term is a1 = 3 .

Maru [420]

$\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{term position}\\ a_1=\textit{first term}\\ d=\textit{common difference}\\[-0.5em] \hrulefill\\ a_1 = 3\\ d= 5\\ n = 25 \end{cases} \implies a_{25} = 3+(25-1)5 \\\\\\ a_{25} = 3+(24)5\implies a_{25} = 3+120\implies a_{25} = 123$

8 0

4 years ago

Ava wants to figure out the average speed she is driving. She starts checking her car’s clock at mile marker 0. It takes her 4 m

umka21 [38]

Speed is 0.75

Equation is n-6= 0.75(t-8)

4 0

3 years ago

Read 2 more answers