Cells conduct cellular respiration to get 36 ATP molecules which contain the majority of the energy in a cell
The correct answer is E)52
When there is Hardy-Weinberg equilibrium like in this case of a single locus with two alleles denoted A and a with frequencies f(A) = p and f(a) = q, the expected genotype frequencies under random mating are f(AA) = p² for the AA homozygotes, f(aa) = q² for the aa homozygotes, and f(Aa) = 2pq for the heterozygotes. Let's put that A is dominant and a is recessive allele. In Hardy-Weinberg equilibrium we have:
p²+2*p*q+q²= 1 p+q=1 p=1-q
f(a) =0.4=q q²=0.4²=0.16=16%
p= 1-0.4=0.6 p²=0.6²=0.36=36%
Percentage of a homozygous genotype in the population is 16%+36%=52%
Answer:
Green turtles live in Tropical Ocean Waters they are affected by climate change, because sea levels rise and stronger storms will erode and destroy there beach habits.
Explanation:
Couldn't find the outlook :)
Answer:
The plants growing on the left will be able to synthesize more required molecules in a better way as compared to the plants on the right.
As plants, on the left, will be receiving all the essential nutrients that is required for functioning properly hence, the will be bale to synthesize all the complex molecules required for growth and surviving.
On the other hand, plants on the right side, will not be able to grow properly as they will not have the required amount of nutrition.
Answer:
In a fruit fly experiment, grey body, normal winged (homozygous dominant) fruit flies were mated with black body, short winged (homozygous recessive) fruit flies. The F1 dihybrid females were then used in a test cross. If the genes are always linked and no crossing over occurs, what would be the predicted ratio in the F2 generation?
GG x bb = Gb, Gb, Gb and Gb F1 generation
grey body heterozygous offspring 4:0
Gb x Gb= GG, Gb, Gb, and bb F2 generation
3:1 three grey body fly and one black body fly
Explanation:
