Answer:
<h2>(2x - 3y)(4x - y) = 8x² - 14xy + 3y²</h2>
Step-by-step explanation:
Use FOIL: <em>(a + b)(c + d) = ac + ad + bc + bd</em>
(2x - 3y)(4x - y) = (2x)(4x) + (2x)(-y) + (-3y)(4x) + (-3y)(-y)
= 8x² - 2xy - 12xy + 3y²
<em>combine like terms</em>
= 8x² + (-2xy - 12xy) + 3y² = 8x² - 14xy + 3y²
If you would like to know how many hours did Judd work outside, you can calculate this using the following steps:
40 hours
outside: 7/10 of the hours = 7/10 * 40 hours = 7/10 * 40 = 28 hours
Judd worked 28 hours outside.
Answer:35.2
Step-by-step explanation:
You have to subtract everything to see what it gives you and what it gives u is $35.2
We have been given that the ages of students in a school are normally distributed with a mean of 15 years and a standard deviation of 2 years.
We are asked to find the percentage of students that are between 14 and 18 years old.
First of all, we will find z-score corresponding to 14 and 18 using z-score formula.
Similarly, we will find the z-score corresponding to 18.
Now we will find the probability of getting a z-score between 
and 
that is 
.
Using normal distribution table, we will get:
Let us convert 
into percentage.
Therefore, approximately 
of the students are between 14 and 18 years old.
