Number of tickets: T.
Number of customers: c
Initially the number of tickets is T0=150, when the group hasn't sold any tickets (c=0). Then the graph must begin with c=0 and T=150. Point=(0,150). Possible options: Graph above to the right and graph below to the left.
They sell the tickets in pack of three tickets per customer c, then each time they sell a pack of three tickets to a customer, the number of tickets is reduced by 3 (-3c). Then the number of tickets, T, the group has left after selling tickets to c customers is:
T=150-3c→T=-3c+150
For T=0→-3c+150=0→150=3c→150/3=c→c=50. The graph must finish with c=50, T=0. Final point=(c,T)=(50,0)
Answer:
The correct graph is above to the right, beginning on vertical axis with T=150 and finishing on horizontal axis with c=50.
The correct equation is T=-3c+150
Answer:
Part A: 1.25g + 14.25 <u><</u> 55.00
Part B: 32 games
Step-by-step explanation:
A:
price per game * games played (1.25g) + money he's already spent (14.25)
must be less than or equal to his total budget (55.00)
equation: 1.25g + 14.25 <u><</u> 55.00
B:
total (55.00) - already spent (14.25) = what he can spend on games (40.75)
55.00 - 14.25 = 40.75
arcade budget (40.75) / cost per game (1.25) = 32.6
because you can't play 0.6 games, 32 games
Answer: -4, -3, -2
Step-by-step explanation:
By inspection, we know 
is a root.
We can thus rewrite the equation as
Answer:
is the correct answer.
Step-by-step explanation:
bisects 
at 
, so, 
