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3 years ago

Anyone know the answers ? this is precal

Mathematics

1 answer:

Nikolay [14]3 years ago

3 0

Step-by-step explanation:

Remember to follow the rule: SohCahToa:

Sin (S) = Opposite/Hypotenuse

Cos (C) = Adjacent/Hypotenuse

Tan (T) = Opposite/Adjacent.

Hypotenuse is always the longest side. Adjacent is the side next to the angle, Opposite is the side opposite of the angle.

Sin(A) = (Opposite/Hypotenuse) = 8/17

Tan(A) = (Opposite/Adjacent) = 8/15

Cos(A) = (Adjacent/Hypotenuse) = 15/17

Sin(B) = (Opposite/Hypotenuse) = 15/17

Tan (B) = (Opposite/Adjacent) = 15/8

Cos (B) = (Adjacent/Hypotenuse) = 8/17

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saveliy_v [14]

Answer:

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Step-by-step explanation:

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3 years ago

What are the potential solutions of In(x^2-25)=0?

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Answer:

$x =\pm \sqrt{26}$

Step-by-step explanation:

Given :-

ln ( x² - 25 ) = 0

And we need to find the potential solutions of it. The given equation is the logarithm of x² - 25 to the base e . e is Euler's Number here. So it can be written as ,

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Which congruence theorem can be used to prove bda = bdc Hl ssa aas sss

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3 years ago

Anyone know the answers ? this is precal​

Anyone know the answers ? this is precal