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ludmilkaskok [199]
3 years ago
6

Anyone know the answers ? this is precal​

Mathematics
1 answer:
Nikolay [14]3 years ago
3 0

Step-by-step explanation:

Remember to follow the rule: SohCahToa:

Sin (S) = Opposite/Hypotenuse

Cos (C) = Adjacent/Hypotenuse

Tan (T) = Opposite/Adjacent.

Hypotenuse is always the longest side. Adjacent is the side next to the angle, Opposite is the side opposite of the angle.

Sin(A) = (Opposite/Hypotenuse) = 8/17

Tan(A) = (Opposite/Adjacent) = 8/15

Cos(A) = (Adjacent/Hypotenuse) = 15/17

Sin(B) = (Opposite/Hypotenuse) = 15/17

Tan (B) = (Opposite/Adjacent) = 15/8

Cos (B) = (Adjacent/Hypotenuse) = 8/17

~

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Given that the quadrilateral ABCD is translated to get quadrilateral A'B'C'D'. The vertex A is at (-5,2) is translated to vertex A' is at (2,-2).

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The translation is y-direction, b, is the difference of y-coordinates of both the points, b = -2-2 = -4.

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