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3 years ago

How is solving literal equations like solving equations in one variable

Mathematics

2 answers:

Soloha48 [4]3 years ago

5 0

Answer:

When given a literal equation, you will often be asked to solve the equation for a

given variable. The goal is to isolate that given variable. The process is the same

process that you use to solve linear equations; the only difference is that you will

be working with a lot more letters, and you may not be able to simplify as much as

you can with linear equations. This packet will hopefully show you the process in a

simple manner so that you will be able to solve literal equations yourself. See

examples before for the method to solving literal equations for a given variable:

nikitadnepr [17]3 years ago

5 0

Answer:

Step-by-step explanation:

To solve a literal equation means to rewrite the equation so a different variable stands alone on one side of the equals sign. We have to be told for which variable we want to solve.

Linear equations in one variable may take the form a x + b = 0 \displaystyle ax+b=0 ax+b=0 and are solved using basic algebraic operations. We begin by classifying linear equations in one variable as one of three types: identity, conditional, or inconsistent. An identity equation is true for all values of the variable.

I hope this helps. Sorry if I could not answer your question!

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Answer:

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2 years ago

James piglet weighs 7 lb his hand weighs 74 oz how many more ounces does the piglet weigh than the hen

zavuch27 [327]

Answer:

38 more ounces.

Step-by-step explanation:

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2 years ago

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2 years ago

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3 years ago

A square is inscribed in a circle with an area of 10 pi square inches. what is the area of the square

Naddik [55]

We need to determine the radius and diameter of the circle. If the area of the circle is 10 pi in^2, then, according to the formula for the area of a circle,

A = 10 pi in^2 = pi*r^2. Thus, 10 in^2 = r^2, and r = radius of circle = sqrt(10) in.

Thus, the diam. of the circle is 2sqrt(10) in. This diam. has the same length as does the hypotenuse of one of the triangles making up the square.

Thus, [ 2*sqrt(10) ]^2 = x^2 + x^2, where x represents the length of one side of the square. So, 4(10) in^2 = 2x^2. Then:
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2 years ago