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Assoli18 [71]
3 years ago
9

Which pair shows equivalent expressions?2(3x+ 2) = 23 x+1 21ę x+ 2) = x+4 2c 21= x+4)= 2

Mathematics
1 answer:
Ket [755]3 years ago
7 0

Answer:

Option (2)

Step-by-step explanation:

Option (1).

2(\frac{2}{5}x+2)=2\frac{2}{5}x+1

\frac{4x}{5}+4=\frac{12}{5}x+1

Therefore, both the sides of the expression are not equal.

False.

Option (2).

2(\frac{2}{5}x+2)=\frac{4}{5}x+4

\frac{4x}{5}+4=\frac{4}{5}x+4

True.

Option (3).

2(\frac{2}{5}x+4)=\frac{4}{5}x+2

\frac{4}{5}x+8=\frac{4}{5}x+2

False.

Option (4).

2(\frac{2}{5}x+4)=2\frac{2}{5}x+8

\frac{4x}{5}+8=\frac{12}{5}x+8

Both the sides are not equal.

False.

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3 years ago
Find the domain of h(x)=x-3/x^3-36x
Dovator [93]

There is some ambiguity here which could be removed by using parentheses.  I'm going to assume that you actually meant:

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h(x) = ---------------

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To determine the domain of this function, factor the denominator:

x^3 - 36x = x(x^2 - 36) = x(x-6)(x+6)

The given function h(x) is undefined when the denominator = 0, which happens at {-6, 0, 6}.

Thus, the domain is "the set of all real numbers not equal to -6, 0 or 6."

Symbolically, the domain is   (-infinity, -6) ∪ (-6, 0) ∪ (0, 6) ∪ (6, +infinity).

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3 years ago
I need help with this!
sashaice [31]

Answer:

Step-by-step explanation:

Let the width be w centimeters.

Then the length = w + 7.

The area A is found from the length multiplied by the width.

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Now we can rearrange this equation to form a quadratic, as follows:

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2 years ago
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butalik [34]

Answer:

90 engines must be made to minimize the unit cost.

Step-by-step explanation:

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Suppose we have a quadratic function in the following format:

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It's vertex is the point (x_{v}, y_{v})

In which

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x value of the vertex. So

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90 engines must be made to minimize the unit cost.

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2 years ago
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MissTica

Answer:

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