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ivanzaharov [21]
3 years ago
6

(2.5 × 10^7) ÷ (5 × 10^4) simplified equation

Mathematics
1 answer:
Zarrin [17]3 years ago
6 0

Answer:

0.5 x 10^3

Step-by-step explanation:

(2.5 x 10^7) /(5 x 10^4)

Divide 2.5 by 5 and subtract the powers. We are subtracting the powers because we are dividing. If we were multiplying, we’d add the powers .

This can be written as

2.5/5 x 10^7-4

0.5 x 10^3

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Help!!!!! Giving out 15 points and a Brainliest to the person who answers correctly
Elis [28]

Answer:

m∠TUW = 90, m∠VUR = 130, m∠VUW = 50

Step-by-step explanation:

Supplementary angles add up to 180!

5 0
3 years ago
What is the value of x?
ryzh [129]

Answer:

Step-by-step explanation:

The top triangle is similar to the whole triangle because of AAA

Then we know that the corresponding sides are similar

9/81=(3x-20)/(3x-20+56)

1/9=(3x-20)/(3x+36)

cross multiply

9(3x-20)=3x+36

27x-180=3x+36

24x=216

x=9

8 0
3 years ago
Help, I’m stuck. Lol.
Darya [45]

Answer:

a. height = 12

b. area = 228

Step-by-step explanation:

a. To find the height, we can use the triangle formed by the side that measures 15, the side that measures 9. and the height. The hypotenuse of the triangle(the longest side opposite of the right angle), is 15. We can then use the Pythagorean Theorem, which states that a^2+b^2=c^2, where c is the hypotenuse, and a and b are the two other sides. In this case, we need to find a leg of the triangle, not the hypotenuse. What do we do? We can first call the height a, and rearrange the Theorem into c^2-b^2=a^2. 15^2=225, 9^2=81, and 225-81=\sqrt{144}=12. Therefore, the height of the parallelogram is \boxed{12}

b. To find the area of the parallelogram, we can use the area formula, which is Base*Height. The base is the flat side. We can find the base by adding 9+10=19, and 19\cdot12=\boxed{228}

6 0
4 years ago
A fence 6 ft high runs parallel to the wall of a house at a distance of 5 ft. Find the length of the shortest ladder that extend
Anettt [7]

Answer:

L = 15.53 ft

Step-by-step explanation:

using diagram which is attached below

now, using Pythagoras theorem

L² = b²  + (5 + x)²...............(1)

using similarity of triangle

\dfrac{x}{6}=\dfrac{5+x}{b}

b=\dfrac{5+x}{x}6

from equation (1)

L^2 = (\dfrac{5+x}{x}6)^2 + (5 + x)^2

     = (5+x)^2(1+\dfrac{36}{x^2})

\frac{\mathrm{d} L^2}{\mathrm{d} x}= 2(5+x)(1+\dfrac{36}{x^2})+(5+x)^2(\dfrac{-2\times 36}{x^3})

\frac{\mathrm{d} L^2}{\mathrm{d} x}= (5+x)(2-\dfrac{72\times 5}{x^3})

for maxima or minima

\frac{\mathrm{d} L^2}{\mathrm{d} x}=0

x = -5 and x =  ∛190  = 5.74

on second derivative 5.74 is the value which comes out to be minimal value which is the distance between the fence and ladder

now,

L² = 241.38

L = 15.53 ft

7 0
3 years ago
What is the interquartile range for the data set? 241, 230, 201, 245, 209, 211, 242, 201, 204, 228, 242, 243 Enter your answer i
creativ13 [48]
The answer is 36. The formula for IQR is Q3-Q1. 

Q3=242.5    Q1=206.5

242.5-206.5=36

So 36 is your IQR
8 0
4 years ago
Read 2 more answers
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