Let us say that the samples for fifty movies is 1 and
samples for thirty five is 2. To solve the test statistic z, we can use the
formula:
z = (p1 – p2) / sqrt [p (1 – p) (1 / n1 + 1 / n2)]
Where,
p1 = is the proportion for sample 1 = 0.36
p2 = is the proportion for sample 2 = 0.23
n1 = number of samples = 50
n2 = number of samples = 35
while p can be calculated using the formula:
p = [p1 * n1 / (n1 + n2)] + [p2 * n2 / (n1 + n2)]
p = [0.36 * 50 / (50 + 35)] + [0.23 * 35 / (50 + 35)]
p = 0.211764705 + 0.094705882
p = 0.306470587
Going back for the calculation of z:
z = (0.36 – 0.23) / sqrt [0.306 (1 – 0.306) (1 / 50 + 1 /
35)]
z = 1.279
Therefore the nearest answer is:
z = 1.29
Answer:
Step-by-step explanation:
1. Find the GCD ( or HCF) of numerator and denominator
<u>GCD of 5 and 14 is 1</u>
2. Divide both the numerator and denominator by the GCD
5 divide 1 and 14 divide 1
3 reduced fraction
5/14
<em>Solution</em><em>,</em>
<em>7</em><em>x</em><em>-</em><em>1</em><em>4</em><em>=</em><em>2</em><em>x</em><em>+</em><em>1</em><em>1</em>
<em>or,</em><em>7</em><em>x</em><em>-</em><em>2</em><em>x</em><em>=</em><em>1</em><em>1</em><em>+</em><em>1</em><em>4</em>
<em>or,</em><em>5</em><em>x</em><em>=</em><em>2</em><em>5</em>
<em>or,</em><em>X=</em><em>2</em><em>5</em><em>/</em><em>5</em>
<em>X=</em><em>5</em>
<em>The </em><em>answer</em><em> </em><em>is</em><em> </em><em>5</em><em>.</em>
<em>hope </em><em>it</em><em> </em><em>helps</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
The arc length is given by:
C=θ/360πd
where:
d=diameter=2*7=14 ft
θ=2/3*180=120
thus the arc length will be:
120/360*π*(2*7)
=14.661 ft
Answer: 14.661 ft
Answer: 3-3n+8e
3-8n+5n+8e
Add -8n+5n
That equals to-3n
You get 3-3n+8e since there is no way more to simplify
