3 years ago

Please help quick!!!

Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

5 0

Answer:

Investigation 1

Step-by-step explanation:

Temperature change reveals a chemical reaction.

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Miguel rented a truck for one day. There was a base fee of $20.95, and there was an additional charge of 83 cents for each mile

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Answer:

254 miles

Step-by-step explanation:

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3 years ago

the sum of 2 numbers is 56.twice the smaller number exceeds one-half the larger number by 22.find the numbers

Alexxandr [17]

Answer:

the numbers are 18 and 38

Step-by-step explanation:

x =smaller integer and y =larger integer

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3 years ago

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Simon pays $9 for 6 visits to swim at the community pool. He pays $18 for 12 visits to swim. How much does it cost for each visi

sergij07 [2.7K]

Answer:

$1.50

Step-by-step explanation:

If you do cost per quantity you would get $9 over 6 visits. Then you divide both sides by 6 because to get to one by 6 it's 6 so when you divide both sides by 6 you would get 1.5 over 1 and all you do is add a zero because you're dealing with money

Hope this helps :)

8 0

3 years ago

In ΔKLM, the measure of ∠M=90°, the measure of ∠L=18°, and KL = 8.3 feet. Find the length of MK to the nearest tenth of a foot.

const2013 [10]

Answer:

2.6 ft

Step-by-step explanation:

8.3/sin 90 = MK/sin 18

MK = 8.3 sin 18 / sin 90

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7 0

4 years ago

xand y are light house. y being 20km due east of x and from a ship due south of x the bearing of y was 055°. what is the distanc

leonid [27]

Answer:

I) |xz| ≈ 28.6 km

II) |yz| ≈ 34.8 km

Step-by-step explanation:

Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)

|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°

Using Trigonometric ratio - SOHCAHTOA

I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20

|xz| = 20 * Tan 55 = 20 * 1.428

|xz| = 28.56 km

|xz| ≈ 28.6 km

II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|

|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°

|yz| = 20 ÷ 0.574 = 34.84 km

|yz| ≈ 34.8 km

4 0

3 years ago