Given:
To find:
The quadrant of the terminal side of 
and find the value of 
.
Solution:
We know that,
In Quadrant I, all trigonometric ratios are positive.
In Quadrant II: Only sin and cosec are positive.
In Quadrant III: Only tan and cot are positive.
In Quadrant IV: Only cos and sec are positive.
It is given that,
Here cos is positive and sine is negative. So, 
must be lies in Quadrant IV.
We know that,
It is only negative because lies in Quadrant IV. So,
After substituting , we get
Therefore, the correct option is B.
Answer:
-12
Step-by-step explanation:
if you divide 96 by -8 you will get you answer to c -12
The difference between the two equations is the + 3. This means the vertex of the parabola will move 3 units to the left at the point (-3, 0)
05.05)On a coordinate plane, the coordinates of vertices R and T for a polygon are R(−6, 2) and T(1, 2).
10/2x2= 10
Explanation:
10 divided by 2=5
5x2=10
