answer
x=6, y=-2
explanation
-2x + 8 = y -------equ 1
3x - y = 22 -------equ 2
u can use any of the simultaneous equation method
using elimination method
rearrange first from -------equ 1
-2x+8=y
-y-2x=-8
multiple through by -1
y+2x=8 -------equ 3
rearrange first from -------equ 2
3x-y=22
-y+3=22 ------equ 4
equate 3 and 4, adding them together
y+2x=8 -------equ 3
-y+3=22 ------equ 4
0+5x=30
5x=30
x=6------equ 5
replace 6 for x in any equation
using -------equ 3
y+2x=8
y+2(5)=8
y+10=8
y=8-10
y=-2
Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that
<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>
<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>
where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.
Then the sum is
<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>
and its magnitude is
||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)
… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))
… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))
… = √(16 + 16 cos(135° - 45°) + 4)
… = √(20 + 16 cos(90°))
… = √20 = 2√5
Answer:
x= -42
Step-by-step explanation:
put the liketerms together
x+35= -7
x=-35-7
note*the operation sign changes after crossing the equal sign
x= -42
Answer: C
Step-by-step explanation:
This describes an expotential function
At t = 0, P = 70
Therefore, C = 70
P = 70 e^kt
Solve for k by plugging in (4,360)
k = 0.4094
plug in t(7 hours)
70 e^(0.4094*7)
The answer roughly equals C
Answer:
C
Step-by-step explanation:
