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Sveta_85 [38]
2 years ago
5

A + b + c = abc(1 + 1 + 1)​

Mathematics
1 answer:
Lera25 [3.4K]2 years ago
6 0
If each letter is 1, abc would be equal to 3.
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Can anyone help me please
galben [10]
The answer is 6 units and 3 fourths
5 0
3 years ago
Read 2 more answers
Answer correctly , will mark brainliest answer !!!!
AveGali [126]

Answer:

x-6

Step-by-step explanation:

(x-5)(x-6)=x^2-11x+30

-6*-5=30

(-6)+(-5)=-11

8 0
3 years ago
Read 2 more answers
*PLS HELP
n200080 [17]

Answer:

  y = 3x +4

Step-by-step explanation:

The equation for the parallel line will have the same x- and y-coefficients, but a different constant. You can put the given point values into the equation to see what the constant needs to be:

  y = 3x + b

  10 = 3·2 + b . . . . . . substitute x=2, y=10

  4 = b . . . . . . . . . . . . subtract 6

The equation of the line is ...

  y = 3x +4

3 0
3 years ago
Show your work !!!!!!!!!!!!
sdas [7]
-1/2 < -x/3 < -1/4 = -6/12 < -x/12 < -3/12

two numbers can go in there....-4/12, and -5/12
7 0
3 years ago
Serena has 3 3/5sq meters of wrapping paper for presents. Her grandmother has 1 1/2sq meters of wrapping paper. How much wrappin
levacccp [35]

Answer:

Total wrapping papers Serena and her grandmother = 51/10

Step-by-step explanation:

Serena's wrapping paper for parents:

  • 3\frac{3}{5}=\frac{18}{5} sq meters

Grandmother's wrapping paper:

  • 1\frac{1}{2}=\frac{3}{2} sq meters

In order to determine the combined wrapping papers for both Serena and grandmother, all we need is to add both.

i.e.

Total papers = Serena's wrapping paper + Grandmother's wrapping paper

                     =\frac{18}{5}+\frac{3}{2}

                     =\frac{36}{10}+\frac{15}{10}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{c}+\frac{b}{c}=\frac{a+b}{c}

                      =\frac{36+15}{10}

                      =\frac{51}{10}

Therefore, total wrapping papers Serena and her grandmother = 51/10

3 0
3 years ago
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