Answer:
Divide each term in yln(4)=ln(x) y ln ( 4 ) = ln ( x ) by ln(4) ln ( 4 ) . Cancel the common factor of ln(4) ln ( 4 ) . Divide y y by 1 1 . Solve for y and replace with f−1(x) f - 1 ( x
Step-by-step explanation:
Answer:
48
Step-by-step explanation:
A) The total number is the sum of all the frequencies
2+5+8+12+11+6=44
Answer: 44
B) The width is (upper limit - lower limit) / 2
(35-21) / 2 = 7
(50-36) / 2 = 7
(65-51) / 2 = 7
(80-66) / 2 = 7
(95-81) / 2 = 7
(110-96) / 2 = 7
Answer: the width is 7
C) The midpoint is the lower limit + the width
36+7=43
Answer: the midpoint is 43
D)The modal is the class with more frequency
In this case 66-80 with 12
Answer: class 66-80
E) We use the width formula
lower limit = 111
width = 7
upper = (width * 2) - lower
upper = (7 * 2) + 111
upper = 125
Answer: class 111-125
