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jek_recluse [69]
3 years ago
6

The volume of a cone is 329.6 cubic inches, and the height is 5.4 inches. Which of the following is the closest to the radius r

of the cone, in inches?
Mathematics
1 answer:
Anna [14]3 years ago
8 0

Answer:

329.6=1/3×16.97r

5.66r=329.6/÷5.66

r=58.23

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Work out the value of R. Give your answer in standard form to an appropriate degree of accuracy.
Mumz [18]

Answer:

R = 8,228,571.43 (Approx)

Step-by-step explanation:

Given:

R = x²/y

x = 4.8 x 10⁵

y = 2.8 x 10⁴

Find:

Value of R

Computation:

R = x²/y

R = (4.8 x 10⁵)²/ (2.8 x 10⁴)

R = 23.04 x 10¹⁰ / (2.8 x 10⁴)

R = 8.22857.. x 10⁶

R = 8,228,571.43 (Approx)

4 0
3 years ago
Point C is located 8 inches from point A and 6 inches from point B. Points A and B are 2 inches apart.
marshall27 [118]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
Suppose the invertible function φ(x) has the domain (−5,11) and the range (−12,1).
Rom4ik [11]

Answer:

Range of \phi^{-1} is (−5,11).

Step-by-step explanation:

Given the invertible function Ф(x) which has the domain (−5,11) and the range (−12,1).

Invertible function is the function that inverses another function i.e if y=Ф(x) then x=g(y) where g is called the inverse of Ф and denoted by\phi^{-1}

Given Ф(x) the function whose domain is (−5,11) and range is (−12,1). Therefore, by definition of invertible function there exist a function g with domain (−12,1) and range (−5,11) which is called the inverse function denoted by \phi^{-1}

Hence, Range of \phi^{-1} is (−5,11)



3 0
3 years ago
Read 2 more answers
What is the value of b?
docker41 [41]
Do do this problem, you need to use the Law of Cosines!

You are trying to find length b, so

b^2 = a^2 + c^2 - 2ab cos B
b^2 = 22^2 + 28^2 - 2(22)(28) cos 34
b^2 = 484 + 784 - 1232 cos 34
b^2 = 1268 - 1232 cos 34
b^2 = 246.6257
b = 15.7 yards

Hope this helps!
3 0
4 years ago
Read 2 more answers
Please help! 20 points + brainliest
klemol [59]

For the first one we divide every element by sqrt3

we get

q+2/sqrt3 =sqrt5/sqrt3

q=(sqrt5-2)/sqrt3

q=sqrt3*sqrt5-2*sqrt3/3

q=sqrt15-2sqrt3/3

which is the third option

For the second one

sqrt(2y-5) +4=8

first we move the 4 to the right

sqrt(2y-5)=4

we remove the square root by bringing to the power of two

2y-5=16

2y=21

y=21/2

y=10 1/2

third option

7 0
3 years ago
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