There are 84 boys in a freshman class of 146 students. Find the ratio of boys to girls.

Of the last 100 customers entering a computer shop, 25 have purchased a computer. If the classical method for computing probabil

Zanzabum

The answer would be C. 0.25 because one in four customers are buying a computer.
1/4 = 0.25

5 0

2 years ago

Which trigonometric ratios can be determined from the triangles? Select all that apply.

Maksim231197 [3]

Where’s the ratios that we can select? can you provide?

3 0

2 years ago

Can someone help me plz

ankoles [38]

The answer should be 4. Take note of the pattern of unit digits of 2^n.

2^1 = 2
2^2 = 4
2^3 = 8
2^4 = 16
2^5 = 32

Every 4 powers, it rotates 2, 8, 6, 4. Since 2020 is divisible by 4, the answer is 4.

8 0

2 years ago

Classify the function as linear or quadratic and identify the quadratic, linear, and constant terms. f(x) = (3x + 2)(−6x − 3)

SOVA2 [1]

Believe the answer is d, though I’m not completely sure. hope this helps

8 0

3 years ago

Read 2 more answers

HELP PLS Given a polynomial function f(x), describe the effects on the Y-intercept, regions where the graph is increasing and de

Mashcka [7]

1. Remarks:

f(x) to f(x)-3 is the whole graph of f(x), shifted 3 units down.

f(x) to -2f(x):

The effect of "multiplication by -" is that the whole graph is reflected with respect to the x axis, so it is turned upside down.

The effect of "multiplication by 2" is that every point is "stretched vertically by a factor of 2" . So for example the point (-1, -4) in the original function, becomes (-1, -8) in the second one. Or (2, 5) would become (2, 10).

The only points that do not change (are not streched vertically) are the roots. For example if (4,0) is an x-intercept (a root) in the original function, (4,0) is still a root in the second one because 2 times 0 is still 0.

2. Consider the polynomial function of degree n:

$f(x)= a_{n} x^{n} +a_{n-1} x^{n-1}+....+a_{2} x^{2}+a_{1} x^{1}+a_{0}$

a. Y-intercept

The y - intercept is the value of the polynomial function at x=0.
So it is f(0)= $a_{0}$ , that is, the constant term of f(x)

in f(x)-3 the y intercept is shifted 3 units down as any other point, so it becomes $a_{0}-3$

In -2f(x), the y-intercept $a_{0}$ becomes $-2a_{0}$

b. Regions of f decreasing or increasing

f(x)-3 is f(x) just shifted down 3 units, so they are both increasing and decreasing in the same intervals of x

-2f(x) is f(x) turned upside down, so -2f(x) is increasing in all intervals f(x) is decreasing and it is decreasing in all intervals f(x) is increasing.

c. End behaviors

By now it is clear that end behaviors of f(x) and f(x)-3 are same, and f(x) with -2f(x) are opposite

d. Evenness, oddness

If f(x) is even, then f(x)=f(-x)

Let g(x)=f(x)-3

g(x)=f(x)-3=f(-x)-3=g(-3), so in this case f(x)-3 is even

If f(x) is odd, then f(-x)=-f(x)

g(x)=f(x)-3=-f(-x)-3,

so -g(x)=f(-x)+3

g(-x)=f(-x)-3,

so g(-x) is not equal to -g(x). Which means f(x)-3 is not odd if f(x) is

Consider f(x)=-2f(x)

If f(x) is even, f(x)=f(-x)

g(x)=-2f(x)=-2f(-x)
g(-x)=-2f(-x)

So g(x)=g(-x), which means -2f(x) is even if f(x) is even

If f(x) is odd, f(x)=-f(-x)

let g(x)=-2f(x)=-2(-f(-x))=2f(-x)

g(-x)=-2f(-x)=-2(-f(x))=2f(x)

so g(-x) is not equal to -g(x), thus -2f(x) is not odd if f(x) is odd.

The conclusions about oddness and evenness can be also derived from the discussions about the graphs.

6 0

2 years ago