First we need to see in which quadrant 11pi/6 lies And it lies in fourth quadrant. And to find the reference angle in the fourth quadrant, we need to subtract the given angle from 2 pi . For e.g if the angle is 5pi/3, then the reference angle is 2pi - (5pi/3) = pi/3 .
So for the given question, reference angle of 11pi/6 is
And that's the required reference angle .
Answer:
quotient = 995
remainder = 3
Step-by-step explanation:
im not sure i did it right but i tried 8 ^ 12
Answer:
a=-5
Step-by-step explanation:
subtract 3 from both sides
15=-3a
divide by -3
a=-5
Answer:
e) Hence 2, -7 are roots of the equation X² + 5X - 14 = 0
Step-by-step explanation:
given equation : X² + 5X - 14 = 0
⇒ X² + 7X - 2X - 14 = 0
⇒ X·(X + 7) - 2·(X + 7) = 0
⇒ (X + 7)·(X - 2) = 0
⇒ X = -7, X = 2
<u>Hence 2, -7 are roots of the equation X² + 5X - 14 = 0</u>
