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4 years ago

The point-slope form of its equation is

Mathematics

2 answers:

Pie4 years ago

4 0

Answer:

y = mx + b

m being the slope

b being the y intercept

Step-by-step explanation:

Simora [160]4 years ago

4 0

Answer:

Point slope formula is as follows:

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How do you re-write this using only positive exponents? 3x^-4/3 (1+2x^5/3)

Kay [80]

$\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}
\\\\\\
and\qquad \quad a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------\\\\
$

$\bf \cfrac{3x^{-\frac{4}{3}}}{3(1+2x^{\frac{5}{3}})}\implies \cfrac{3}{3}\cdot \cfrac{1}{x^{\frac{4}{3}}}\cdot \cfrac{1}{(1+2x^{\frac{5}{3}})}\implies \cfrac{1}{x^{\frac{4}{3}}(1+2x^{\frac{5}{3}})}$

$\bf \cfrac{1}{x^{\frac{4}{3}}+2x^{\frac{5}{3}}x^{\frac{4}{3}}}\implies \cfrac{1}{x^{\frac{4}{3}}+2x^{\frac{5}{3}+\frac{4}{3}}}\implies \cfrac{1}{x^{\frac{4}{3}}2x^{\frac{9}{3}}}\implies \cfrac{1}{x^{\frac{4}{3}}+2x^3}
\\\\\\
\cfrac{1}{\sqrt[3]{x^4}+2x^3}\implies \cfrac{1}{x\sqrt[3]{x}+2x^3}\implies \cfrac{1}{x(\sqrt[3]{x}+2x^2)}$

8 0

4 years ago

100 divided by 13.5 plus 24

Stella [2.4K]

100/13.5 + 24 = 31.41 approximitely

7 0

4 years ago

Read 2 more answers

Is the relation a function? Why or why not?

tatuchka [14]

Answer: it is c

Step-by-step explanation:

It has two of the same domain

7 0

3 years ago

Melissa has a student dictionary on her desk. Her dictionary contains 90 pages. In this dictionary, more words start with the le

PolarNik [594]

Answer:

probability that the page opened will start with S

Step-by-step explanation:

14/90

0.15556

4 0

3 years ago

What is the solution to the system of equations graphed below? y = x - 2 y = 4x - 5

ololo11 [35]

There are 3 available methods - Substitution , Elimination and Matrix.

The substitution method is used to eliminate one of the variables by replacement.

The elimination method is used for solving linear systems.

A Matrix is an array of numbers.

Lets use Substitution to solve this system.

$x-2=4x-5$

$-2=4x-5-x$

$-2=(4x-x)-5

 
$

$-2=3x-5$

$-2+5=3x$

$3=3x$

$3=3x / 3$

$x=1$

Now substitute $x=1$

$y=x-2$

$y=1-2

 
$

$y=-1

$

Hence - $x=1
 
y=-1$

6 0

3 years ago