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3 years ago

100 divided by 13.5 plus 24

Mathematics

2 answers:

Stella [2.4K]3 years ago

7 0

100/13.5 + 24 = 31.41 approximitely

katovenus [111]3 years ago

3 0

31.41 is the right answer for this question

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Let's say we have a triangle with sides called a, b, and c, and that b is the base. Our triangle has a height that we'll call h.

Irina18 [472]

Answer:

16.34 square inches.

Step-by-step explanation:

Given:

Base of triangle, b = 3 inches

Height of triangle, h = 10.89 inches

Question asked:

What is the area of this triangle in square inches?

Round your answer to the nearest hundredths place .

Solution:

As we know,

$Area\ of\ triangle =\frac{1}{2} \times base\times height$

$=\frac{1}{2} \times3\times10.89\\\\ =\frac{32.67}{2} \\\\ =16.335$

As, we have to find the answer to the nearest hundredths place, hence the area of triangle will be 16.34 square inches.

7 0

3 years ago

Sisqo score 10 points in the first half of the game. In the second half he made four shots, all three pointers. Which of the fol

olga_2 [115]

Answer:

You didn't provided the answer choices, but the answer is he scored 22 points in total.

Step-by-step explanation:

5 0

3 years ago

Pachacha [2.7K]

Answer:

New area: 12ft^2

Step-by-step explanation:

1/3 of 9 is 3

1/3 of 12 is 4

Area = l x w

so 3 x 4 = 12

4 0

3 years ago

Find the product of z1 and z2, where z1 = 7(cos 40° + i sin 40°) and z2 = 6(cos 145° + i sin 145°).

Oduvanchick [21]

For two complex numbers $z_1=re^{i\theta}=r(\cos\theta+i\sin\theta)$ and $z_2=se^{i\varphi}=s(\cos\varphi+i\sin\varphi)$ , the product is

$z_1z_2=rse^{i(\theta+\varphi)}=rs(\cos(\theta+\varphi)+i\sin(\theta+\varphi))$

That is, you multiply the moduli and add the arguments. You have $z_1=7e^{i40^\circ}$ and $z_2=6e^{i145^\circ}$ , so the product is

$z_1z_2=7\times6(\cos(40^\circ+145^\circ)+i\sin(40^\circ+145^\circ)=42(\cos185^\circ+i\sin185^\circ)=42e^{i185^\circ}$

3 0

3 years ago

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Which of the following expression is equivalent to sin(5x) ?

RSB [31]

$Use:\\sin(x+y)=sinxcosy+sinycosx\\-------------------------\\sin5x=sin(3x+2x)=sin3xcos2x+sin2xcos3x\\\\Answer:e)$

5 0

2 years ago

Read 2 more answers