Answer:
The volume of a right circular cone that has a height of 16 m and a base with a circumference of 14.7 m is 3,620.62 m³
Step-by-step explanation:
The right cone (or cone of revolution, or right circular cone) is the solid of revolution formed by rotating a right triangle around one of its legs. The bottom circle of the cone is called the base. That is, a cone is a three-dimensional figure with a circular base. A curved surface connects the base and the vertex.
The volume of a 3-dimensional solid is the amount of space it occupies.
The volume V of a cone with radius r is one-third the area of the base B times the height h. This is:
![V=\frac{1}{3}*A*h](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%2AA%2Ah)
where A=π*r²
Then: V=
*π*r²*h
In this case r=14.7 m and h=16 m. Replacing:
V=
*π*(14.7 m)²*16 m
Solving, you get:
V=3,620.62 m³
<u><em>The volume of a right circular cone that has a height of 16 m and a base with a circumference of 14.7 m is 3,620.62 m³</em></u>