Cobalt has an atomic number (Z) of 27, which means the nuclei of all its isotopes have 27 protons. Cobalt 60 has an atomic mass of 60, so it has 60-27 = 33 neutrons.
The mass of 27 isolated protons plus the mass of 33 isolated neutrons would be:
27*(1.007825 u) + 33*(1.008665 u) = 60.497220 u
The actual mass of the nucleus of 60-Co is 59.933820 u.
Mass defect: 60.497220 u - 59.933820 u = 0.563400 u
The mass defect is equal to the binding energy of a nucleus.
using the fact that 1 u = 931.5 MeV/c^2
(0.563400 u)*(931.5 MeV/u) = 524.807 MeV
Answer: x= 34/7
Step-by-step explanation:hope this helps!
As per question,
Now, multiply 100 with both numbers :
As if we reguce to lowest term, it will be a very lengthy answer. So,
will ne the answer.
~Benjemin360
Answer: B.792
Step-by-step explanation:
Answer: hope this helps
Step-by-step explanation:
Simplifying
1.17 + -0.07a + (-3.92a) = 0
Combine like terms: -0.07a + (-3.92a) = -3.99a
1.17 + -3.99a = 0
Solving
1.17 + -3.99a = 0
Solving for variable 'a'.
Move all terms containing a to the left, all other terms to the right.
Add '-1.17' to each side of the equation.
1.17 + -1.17 + -3.99a = 0 + -1.17
Combine like terms: 1.17 + -1.17 = 0.00
0.00 + -3.99a = 0 + -1.17
-3.99a = 0 + -1.17
Combine like terms: 0 + -1.17 = -1.17
-3.99a = -1.17
Divide each side by '-3.99'.
a = 0.2932330827
Simplifying
a = 0.2932330827