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3 years ago

PLEASE HELP DUE SOON

Mathematics

1 answer:

marishachu [46]3 years ago

6 0

Answer:

Step-by-step explanation:

NOOOOOO IM NOT GONNAAA HELPPPPPP BC THIS IS 2ND GRADE MATH AND U SHOULD KNOW THIS

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How do you do these?

diamong [38]

Answer:

A kite with a 100 foot-long string is caught in a tree. When the full length of the string is stretched in a straight line to the ground, it touches the ground a distance of 30 feet from the bottom of the tree. Find the measure of the angle between the kite string and the ground.

17°

27°

63°

73°

Step-by-step explanation:

7 0

3 years ago

There are 91 rooms in a hotel.52 rooms are reserved. What fraction of the rooms are reserved?

Marat540 [252]

to find remaining rooms 91-52=39

turn into a fraction =39/91

answer=39/91

6 0

3 years ago

The rate at which a quantity of a radioactive substance decays is proportional to the quantity of the substance. The constant of

Butoxors [25]

Answer:

$\frac{dN}{dt} =$ λN N(0) = 6

N(t) = N₀e^(λt)

Applying the inital value condition

N(t) = 6e^(λt)

Step-by-step explanation:

Summarizing the information briefly and stating the variables in the problem.

t = time elapsed during the decay

N(t) = the amount of the radioactive substance remaining after time t

λ= The constant of proportionality is called the decay constant or decay rate

Given the initial conditions

N(0) = N₀ = 6

The rate at which a quantity of a radioactive substance decays ( $\frac{dN}{dt}$ ) is proportional to the quantity of the substance (N) and λ is the constant of proportionality is called the decay constant or decay rate :

$\frac{dN}{dt} =$ λN

N(t) = N₀e^(λt) ......equ 1

substituting the value of N₀ = 6 into equation 1

N(t) = 6e^(λt)

3 0

3 years ago

Midsegments geometry acellus pls helppfpfpff

Anika [276]

Answer:

BC = 28

Step-by-step explanation:

The midsegment DF is half the measure of the third side BC , then

BC = 2 × DF = 2 × 14 = 28

5 0

3 years ago

Divide 6k2-15-5 by 3k

TEA [102]

Based on the question above, I believe that '6k2' would be $(6k^2)$ . So by this, I would continue to with the following expression as: $6k^2-15-5\div3k$

$Simplify: \frac{5}{3} \\ \\ ((6 * (k2)) - 15) - ( \frac{5}{3} *k) \\ \\ ((2*3k^2) - 15) - \frac{5k}{3} \\ \\ \boxed{\boxed{6k^2 - 15 = \frac{6k^2-15}{1} = \frac{(6k^2-15)*3}{3} }} \\ \\ (pull \ out \ like \ terms) \\ \\ 6k^2 - 15 = 3 * (2k^2 - 5) \\ \\ Factoring: 2k^2 - 5$

And by this, in order for us to fully understand that this would be true, the following would enable us to understand.

$\Rightarrow \left[\begin{array}{ccc}A+B) * (A-B) =\\
 A2 - AB + BA - B2 =\\
 A2 - AB + AB - B2 = \\
 A2 - B2\end{array}\right] \Leftarrow$

$\boxed{\bf{ \frac{3*(2k^2-5)*3-(5k)}{3} = \frac{18k^2-5k-45}{3} }}$

$Factoring : 18k^2 - 5k - 45 \\ \\ \left[\begin{array}{ccc} -810 + 1 = -809 \\
 -405 + 2 = -403 \\
 -270 + 3 = -267\\ -162 + 5 = -157 \\
 -135 + 6 = -129 \\
 -90 + 9 = -81 
 
 
\end{array}\right]$

$(Your \ Answer) : \boxed{\boxed{\bf{ \frac{18k^2-5k-45}{3} }}}$

4 0

4 years ago