A "hole" is created when a factor can be crossed out of the numerator and denominator.
x^2 - x - 2 factors into (x - 2)(x + 1) both of which can be crossed out or canceled with the factors in the numerator. That creates very really tiny holes at x = 2 and x = - 1.
Answer:
Step-by-step explanation:
d = 2
arc length of semicircle = ½×circumference = ½×πd = π
perimeter of semicircle = π + d = π+2
Given:
Values of a polynomial P(x).




To find:
The remainder when P(x) is divided by (x+5).
The remainder when P(x) is divided by (x-3).
Solution:
If a polynomial P(x) is divided by (x-a), then the remainder is P(a).
If the polynomial P(x) is divided by (x+5), then the remainder is P(-5).

Therefore, the remainder is -2 when P(x) is divided by (x+5).
If the polynomial P(x) is divided by (x-3), then the remainder is P(3).

Therefore, the remainder is 7 when P(x) is divided by (x-3).
Answer:
The Answer is 6
Step-by-step explanation:
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