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3 years ago

Please help I’ll mark you as a brainliest

Mathematics

1 answer:

masha68 [24]3 years ago

8 0

Answer:

divide 150 by 32 to get 4

Step-by-step explanation:

i used a calculator sorry if wrong im new

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If a triangle has side lengths 14,48, and 50 units what type of triangle is it an acute an obtuse a right or no solution.

Snezhnost [94]

Answer:

No solution

Step-by-step explanation:

we know that

The <u>Triangle Inequality Theorem</u> states that the sum of any 2 sides of a triangle must be greater than the measure of the third side

In this problem

$48+50>14$

$98>14$ -----> is not true

therefore

You can't build a triangle with those dimensions

4 0

3 years ago

To calculate 587 ÷ 1,000, how many decimal points to the left should the decimal in 587 move?

VARVARA [1.3K]

Answer:

3 decimal points

Step-by-step explanation:

The trick here is to count the zeros.

8 0

2 years ago

PICK ONE OF THE FOLLOWING (imagine added)

Gala2k [10]

Answer:

Step-by-step explanation:

3 0

1 year ago

Lease someone help me im so confused on how to find it.

LiRa [457]

The answer is D you simply get one point and move it 4 squares down and 6 squares to the right

5 0

3 years ago

Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex

siniylev [52]

Answer:

$\large \boxed{\sf \ \ \ p=-11 \ \ \ }$

Step-by-step explanation:

Hello,

$\alpha \text{ and } \beta \text{ are the roots of the following equation}$

$2x^2+6x-7=p$

It means that

$2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\$

And we know that

$\alpha= 2\cdot \beta$

So we got two equations

$2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1$

For $\beta =0, \ \ \alpha =0, \ \ p = -7$

For $\beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11$

I assume that we are after two different roots so the solution for p is p=-11

b) $\alpha +2 =-2+2=0 \ and \ \beta+2=-1+2=1$

So a quadratic equation with the expected roots is

$x(x-1)=x^2-x$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0

3 years ago