Answer:
32, percentage increaced by 25% =40
Step-by-step explanation:
Answer:
Contradictrion
Step-by-step explanation:
First write an equation. If the total is 289, then that goes one the right side of the =. Sociology textbooks will be x. If there were 65 less than x, it will be 65-x. Lets set it up:
x + 65 -x =289
Then combine like terms.
65 = 289
There are no values of x that make the equation true. The input is a contradiction.
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NO ANSWER</u></h2>
7 inches → 280 yards
1 inch → 280 ÷ 7 = 40 yards
5 inches → 40 x 5 = 200 yards
Area = 280 x 200 = 56 000 yards
Answer: 56000 yards
Answer:
(A) The distance from the drinking fountain to the bench is 4, and the distance from the bench to the center of the slide is 3 because if you add -4 and 0 you will get 4 and if you subtract 5 and 2 you will get 3.
(B) The type of triangle that is created is an obtuse triangle because when you connect the 3 locations it creates an obtuse triangle on the coordinate grid.
Step-by-step explanation:
I already explained in the answer. Hope this helps and gets you an 100%
:)
Answer:
no, the confidence interval for the standard deviation σ cannot be expressed as 15.7
4.7There are three ways in which you can possibly express a confidence interval:
1)
inequalityThe two extremities of the interval will be each on one side of the "less then" symbol (the smallest on the left, the biggest on the right) and the symbol for the standard deviation (σ) will be in the middle:
11.0 < σ < 20.4
This is the first interval given in the question and it means <span>that the standard deviation can vary between 11.0 and 20.4
2)
interval</span>The two extremities will be inside a couple of round parenthesis, separated by a comma, always <span>the smallest on the left and the biggest on the right:
(11.0, 20.4)
This is the second interval given in the question.
3)
point estimate </span><span>
margin of error</span>
This is the most common way to write a confidence interval because it shows straightforwardly some important information.
However,
this way can be used only for the confidence interval of the mean or of the popuation, not for he confidence interval of the variance or of the standard deviation.
This is due to the fact that in order to calculate the confidence interval of the standard variation (and similarly of the variance), you need to apply the formula:

which involves a χ² distribution, which is not a symmetric function. For this reason, the confidence interval we obtain is not symmetric around the point estimate and the third option cannot be used to express it.