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3 years ago

How do I solve this problem below!

Mathematics

2 answers:

Digiron [165]3 years ago

6 0

The correct answer is five dollars and fourth four cents.

mojhsa [17]3 years ago

3 0

Answer:

$5.44

Step-by-step explanation:

$1.75 + $1.26 + $1.08 + $0.52 = $4.56

$10.00 - $4.56 = $5.44

You might be interested in

The table shown below represents a function. Which of the following values could not be used to complete the table?

11111nata11111 [884]

Answer:

The answer to your question is: letter B

Step-by-step explanation:

Function definition: a function is a relation from a set of inputs to a set of outputs.

The most important about functions is that each input is related to one and only one output. Then there are not repeated values of inputs.

In the exercise, the inputs are -10, -25, -5, and the outputs are 5, 10, 15 and 20.

So, to solve this exercise, look for a number in the options that will not be repeated in the inputs,

Then,

- 20 is a possible option because is not repeated

-5 is not an option to complete the table because 5 already exist.

- 15 is a possible option because is not repeated previously.

3 0

3 years ago

Easy question pls anwser

defon

Answer:

A, C, D

Step-by-step explanation:

Since 15 is a positive integer, it can be represented in positive situations.

15 students add classes to schedule. = 15

15 points are taken away. = -15

15 point are given. = 15

15 dollars has been added to your salary = 15

15 dollars have been taken from your salary = -15

6 0

3 years ago

Read 2 more answers

How do you work out nth term

Mnenie [13.5K]

Answer:

plug in "n" in the formula to get an answer

Step-by-step explanation:

7 0

3 years ago

Data is a pieces of information true or false

Maru [420]

True because it is used to collect information on data tables and other things.

6 0

3 years ago

I'm having trouble with #2. I've got it down to the part where it would be the integral of 5cos^3(pheta)/sin(pheta). I'm not sur

Butoxors [25]

$\displaystyle\int\frac{\sqrt{25-x^2}}x\,\mathrm dx$

Setting $x=5\sin\theta$ , you have $\mathrm dx=5\cos\theta\,\mathrm d\theta$ . Then the integral becomes

$\displaystyle\int\frac{\sqrt{25-(5\sin\theta)^2}}{5\sin\theta}5\cos\theta\,\mathrm d\theta$
$\displaystyle\int\sqrt{25-25\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$
$\displaystyle5\int\sqrt{1-\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$
$\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$

Now, $\sqrt{x^2}=|x|$ in general. But since we want our substitution $x=5\sin\theta$ to be invertible, we are tacitly assuming that we're working over a restricted domain. In particular, this means $\theta=\sin^{-1}\dfrac x5$ , which implies that $\left|\dfrac x5\right|\le1$ , or equivalently that $|\theta|\le\dfrac\pi2$ . Over this domain, $\cos\theta\ge0$ , so $\sqrt{\cos^2\theta}=|\cos\theta|=\cos\theta$ .

Long story short, this allows us to go from

$\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$

to

$\displaystyle5\int\cos\theta\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$
$\displaystyle5\int\dfrac{\cos^2\theta}{\sin\theta}\,\mathrm d\theta$

Computing the remaining integral isn't difficult. Expand the numerator with the Pythagorean identity to get

$\dfrac{\cos^2\theta}{\sin\theta}=\dfrac{1-\sin^2\theta}{\sin\theta}=\csc\theta-\sin\theta$

Then integrate term-by-term to get

$\displaystyle5\left(\int\csc\theta\,\mathrm d\theta-\int\sin\theta\,\mathrm d\theta\right)$
$=-5\ln|\csc\theta+\cot\theta|+\cos\theta+C$

Now undo the substitution to get the antiderivative back in terms of $x$ .

$=-5\ln\left|\csc\left(\sin^{-1}\dfrac x5\right)+\cot\left(\sin^{-1}\dfrac x5\right)\right|+\cos\left(\sin^{-1}\dfrac x5\right)+C$

and using basic trigonometric properties (e.g. Pythagorean theorem) this reduces to

$=-5\ln\left|\dfrac{5+\sqrt{25-x^2}}x\right|+\sqrt{25-x^2}+C$

4 0

3 years ago

Read 2 more answers