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3 years ago

How do I solve this problem below!

Mathematics

2 answers:

Digiron [165]3 years ago

6 0

The correct answer is five dollars and fourth four cents.

mojhsa [17]3 years ago

3 0

Answer:

$5.44

Step-by-step explanation:

$1.75 + $1.26 + $1.08 + $0.52 = $4.56

$10.00 - $4.56 = $5.44

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Look at this prism and its net. Rectangular prism with length labeled 5 meters, width labeled 7 meters, and height labeled 12 me

kaheart [24]

There will be three pairs of matching sides: one pair 5x7, one pair 5x12 and one pair 12x7. We can compute the are of each side (in pairs) and then add up the total:

$A_{surf}=2\times(l \times w)+2\times(l \times h)+2\times(h \times w)$
$A_{surf}=2\times(5\times7)+2\times(5\times12)+2\times(12\times7)$
$A_{surf}=2\times35+2\times60+2\times84$
$A_{surf}=70+120+168$
$A_{surf}=358$
$A_{surf}=358m^{2}$

5 0

3 years ago

Help please it’s due soon

MArishka [77]

Answer: 60 degrees

Step-by-step explanation: triangles are come to 180 if you add all angles correctly. therefore if you do 180-90-30, you'll get 60.

4 0

3 years ago

A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the

Vedmedyk [2.9K]

(a) Using Newton's Law of Cooling, $\dfrac{dT}{dt} = k(T - T_s)$ , we have $\dfrac{dT}{dt} = k(T - 75)$ where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get $\dfrac{dT}{T - 75} = k dt$ . Integrate both sides to get $\ln|T - 75| = kt + C$ .

Since $T(0) = 185$ , we solve for C:
$|185 - 75| = k(0) + C\ \Rightarrow\ C = \ln 110$
So we get $\ln|T - 75| = kt + \ln 110$ . Use T(30) = 150 to solve for k:
$\ln| 150 - 75 | = 30k + \ln 110\ \Rightarrow\ \ln 75 - \ln 110= 30k \Rightarrow \\ k= \frac{1}{30}\ln (75/110) = \frac{1}{30}\ln(15/22)$

So

$\ln|T - 75| = kt + \ln 110 \Rightarrow |T - 75| = e^{kt + \ln110} \Rightarrow \\ \\
|T - 75| = 110e^{kt} \Rightarrow T - 75 = \pm110e^{(1/30)\ln(15/22)t} \Rightarrow \\
T = 75 \pm110e^{(1/30)\ln(15/22)t}$

But choose Positive because T > 75. Temp of turkey can't go under.

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} \\
T(45) = 75 + 110e^{(1/30)\ln(15/22)(45)} = 136.929 \approx 137{}^{\circ}F$

(b)

$T(t) = 75 + 110e^{(1/30)\ln(15/22)t} = 75 + 110(15/22)^{t/30} \\
100 = 75 + 110(15/22)^{t/30} \\
25 = 110(15/22)^{t/30} 
\frac{25}{110} = (15/22)^{t/30} \\
\ln(25/110) / ln(15/22) = t/30 \\
t = 30\ln(25/110) / ln(15/22) \approx 116\ \mathrm{min}$

Dogs of the AMS.

4 0

3 years ago

Which fraction is equivalent to 5(z+3)-4(1+p)? A. 15z-4p B. 5z+19+4p C. 5z+11-4p

Mila [183]

C 5z+11-4p.

5(z+3)-4(1+p)
5z+15-4-4p
5z+11-4p

8 0

3 years ago

Find the value of x. Round to the nearest tenth A. 11.0 B. 9.1 C. 4.2 D. 23.7

Greeley [361]

A tell me if it’s right

5 0

3 years ago