Ella played a math game and had the five cards shown.

2.2 Your friend Sam, mistakenly wrote down the multiples of 10 as: 1; 2; 5; and 10.

kkurt [141]

Do you know the multiples of 10

6 0

1 year ago

Find the distance between the two points in simplest radical form. (-1,9) and (4, -3)

jolli1 [7]

Answer:

GIVEN BY POINTS :-

( -1, 9) , ( 4 , -3)

Here ,

$\bullet \: \: x _{1} = - 1 \\ \bullet \: \: x _{2} = 4 \\ \bullet \: \: y _{1} = 9 \\ \bullet \: \: y _{2} = - 3 \\$

Using Distance formula :

$= > \sf d = \sqrt{( {x _{2} - x _{1}) }^{2} + {( {y _{2} - y _{1}) }^{2} } } \\ \\ = > \sf d = \sqrt{ ({ 4 + 1)}^{2} + { ( - 3 - 9)}^{2} } \\ \\ = > \sf d = \sqrt{ {5}^{2} + {( - 12)}^{2} } \\ \\ = > \sf d = \sqrt{25 + 144} \\ \\ = > \sf d = \sqrt{169} \\ \\ = > \boxed{ \sf{ d = 13\:units }}\\$

8 0

3 years ago

What is the additive inverse of -2 + 8i?

tatuchka [14]

Answer:

2 - 8i

Step-by-step explanation:

The additive inverse of something is basically the opposite of it. Another way to say this is that when you add the additive inverse to -2 + 8i, it will equal 0.

An example:

The additive inverse of 7 is -7 because not only is it the opposite, but also when you add 7 and -7, it equals 0.

To solve

So all you need to do is find the opposite of -2 + 8i. You can write it as:

-(-2 + 8i) With the negative in the front because we want to find the opposite.

This then equals:

2 - 8i

You can check your answer by adding -2 + 8i and 2 - 8i to see if it equals 0:

(-2 + 8i) + (2 - 8i) → and it does equal 0

ANSWER: 2 - 8i

Hope you understand and that this helps with your question! :)

8 0

2 years ago

PLEASE HELP!!! So the answer I got was 19.14 however that is not the correct answer. How do I solve this problem. Not sure what

Mamont248 [21]

Check the picture below.

so we know the radius of the semicircle is 2 and the rectangle below it is really a 4x4 square, so let's just get their separate areas and add them up.

$\stackrel{\textit{area of the semicircle}}{\cfrac{1}{2}\pi r^2}\implies \cfrac{1}{2}(\stackrel{\pi }{3.14})(2)^2\implies 3.14\cdot 2\implies 6.28 \\\\\\ \stackrel{\textit{area of the square}}{(4)(4)}\implies 16 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{sum of both areas}}{16+6.28=22.28}~\hfill$