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3 years ago

How to simplify fractions

Mathematics

1 answer:

serious [3.7K]3 years ago

5 0

Step-by-step explanation:

$\frac{2}{3} + \frac{2}{9} \\\\\frac{6+2}{9}\\\\\frac{8}{9}$

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PLZ HELP!

AnnyKZ [126]

Answer:

$0.25

Step-by-step explanation:

Site A pays ...

... $0.65 × 5 = $3.25

Site B pays ...

... y = 0.60·5 = 3.00 . . . dollars

Site A pays more by ...

... $3.25 - 3.00 = $0.25

_____

You can also look at the difference in unit rates. Site A pays $0.65 per photo, while site B pays $0.60 per photo, a difference of $0.65 - 0.60 = $0.05 per photo. Then 5 photos will be worth $0.05 × 5 = $0.25 more at Site A.

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2 years ago

Which line is most likely to have a slope of 10 ?

hodyreva [135]

The line that is most likely to have a slope of 10 is the second one down

6 0

3 years ago

Read 2 more answers

if the angles of triangle RST and measure of angle R= (9x-2)degrees, and the measure of angle S=(4x+36) degrees, and measure of

Salsk061 [2.6K]

Answer:

R, T, S

Step-by-step explanation:

R+S+T=180 degrees

9x-2+4x+36+5x+20=180

18+54x=180

54x=162

x=3

R=9*3-2 (substitute x with 3)

R=25

S=4*3+36

S=48

T=5*3+20

T=35

Shortest to longest: R, T, S

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2 years ago

A whale-watching tour boat cannot operate if the total passenger weight is more than 3 comma 150 comma 000 grams. What is the m

Andru [333]

Answer:

Step-by-step explanation:

7 0

3 years ago

The distribution of weights for newborn babies is approximately normally distributed with a mean of 7.4 pounds and a standard de

blsea [12.9K]

Answer:

1. 15.87%

2. 6 pounds and 8.8 pounds.

3. 2.28%

4. 50% of newborn babies weigh more than 7.4 pounds.

5. 84%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 7.4 pounds

Standard Deviation, σ = 0.7 pounds

We are given that the distribution of weights for newborn babies is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

1.Percent of newborn babies weigh more than 8.1 pounds

P(x > 8.1)

$P( x > 8.1) = P( z > \displaystyle\frac{8.1 - 7.4}{0.7}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 8.1) = 1 - 0.8413 = 0.1587 = 15.87\%$

15.87% of newborn babies weigh more than 8.1 pounds.

2.The middle 95% of newborn babies weight

Empirical Formula:

Almost all the data lies within three standard deviation from the mean for a normally distributed data.
About 68% of data lies within one standard deviation from the mean.
About 95% of data lies within two standard deviations of the mean.
About 99.7% of data lies within three standard deviation of the mean.

Thus, from empirical formula 95% of newborn babies will lie between

$\mu-2\sigma= 7.4-2(0.7) = 6\\\mu+2\sigma= 7.4+2(0.7)=8.8$

95% of newborn babies will lie between 6 pounds and 8.8 pounds.

3. Percent of newborn babies weigh less than 6 pounds

P(x < 6)

$P( x < 6) = P( z > \displaystyle\frac{6 - 7.4}{0.7}) = P(z < -2)$

Calculation the value from standard normal z table, we have,

$P(x < 6) =0.0228 = 2.28\%$

2.28% of newborn babies weigh less than 6 pounds.

4. 50% of newborn babies weigh more than pounds.

The normal distribution is symmetrical about mean. That is the mean value divide the data in exactly two parts.

Thus, approximately 50% of newborn babies weigh more than 7.4 pounds.

5. Percent of newborn babies weigh between 6.7 and 9.5 pounds

$P(6.7 \leq x \leq 9.5)\\\\ = P(\displaystyle\frac{6.7 - 7.4}{0.7} \leq z \leq \displaystyle\frac{9.5-7.4}{0.7})\\\\ = P(-1 \leq z \leq 3)\\\\= P(z \leq 3) - P(z < -1)\\= 0.9987 -0.1587= 0.84 = 84\%$

84% of newborn babies weigh between 6.7 and 9.5 pounds.

7 0

3 years ago