The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
Answer:
no one can do it
Step-by-step explanation:
Answer:
x= 12/5
Step-by-step explanation:
Also, if you mean simplify, it can no longer be simplified, so it would just be
1/4x-3/5.
Hope this helps!!
Plz let me no if I'm wrong.
Answer:
B
Step-by-step explanation:
Composite because it can go into 2 and other numbers
