Subject : Pythagorean Theorem
1 answer:
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Hello,
Rectangle A: 6cm (x+2)cm
Rectangle B: 3cm (2x+1)cm
The formula for the perimeter of a rectangle is: P=2(base+height)
Then:
![P_A=2(b+h) \\ P_A=2*[6+(x+2)] \\ P_A=2*(x+8) \\ P_A=2x+16 \\ \\ \\ P_B=2(b+h) \\ P_B=2*[3+(2x+1)] \\ P_B=2*(2x+4) \\ P_B=4x+8 ](https://tex.z-dn.net/?f=P_A%3D2%28b%2Bh%29%20%5C%5C%20P_A%3D2%2A%5B6%2B%28x%2B2%29%5D%20%5C%5C%20P_A%3D2%2A%28x%2B8%29%20%5C%5C%20P_A%3D2x%2B16%20%5C%5C%20%20%5C%5C%20%20%5C%5C%20P_B%3D2%28b%2Bh%29%20%5C%5C%20P_B%3D2%2A%5B3%2B%282x%2B1%29%5D%20%5C%5C%20P_B%3D2%2A%282x%2B4%29%20%5C%5C%20P_B%3D4x%2B8%0A)
But we know that the perimeters are the same, so:
With the answer of A, we realize that this figure is actually a square.
Rectangle A: 6cm (x+2)cm
Rectangle B: 3cm (2x+1)cm
The formula for the perimeter of a rectangle is: P=2(base+height)
Then:
But we know that the perimeters are the same, so:
With the answer of A, we realize that this figure is actually a square.