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4 years ago

Sean answer 63 questions correctly on a test of 81 questions what fractional part of the question did he answer incorrectly

Mathematics

1 answer:

ElenaW [278]4 years ago

6 0

Answer:

Sean got 63/81 questions right as a fraction.

Step-by-step explanation:

Sean got 63/81 correct. If there was a total of 81 questions, you put that as your denominator.

Now ask yourself: Can you simplify?

Yes you can.

You divide each number from the fraction by 9.

63 / 9 = 7

81 / 9 = 9

7/9 questions that Sean got correct.

If you also want a percentage + grade, Sean would get 77% which would be a C+

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storchak [24]

Answer:

The equilibrium point is at x = 6

Step-by-step explanation:

Given

$Demand (q) = \frac{18}{x}$

$Supply (q) = \frac{x}{2}$

Required

Determine the equilibrium point

The equilibrium point is determined by

$Demand = Supply$

Substitute values for Demand and Supply

$\frac{18}{x} = \frac{x}{2}$

Cross Multiply

$x * x = 18 * 2$

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Take positive square root of both sides

$x = 6$

Hence;

<em>The equilibrium point is at x = 6</em>

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3 years ago

The lengths of all sides of a triangle are integers when measured in decimeters. One of the sides has length of 1 dm and another

hram777 [196]

Answer:

The perimeter is 7 dm

Step-by-step explanation:

we know that

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Let

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case a)

1+c>3

c>2 dm

case b)

1+3> c

4 > c

rewrite

c<4 dm

The solution for c is the interval------> (2,4)

therefore

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3 years ago

Can someone please solve this for me btw I’m suppose to be dividing that question using long division

SIZIF [17.4K]

Answer:

0.343

Step by step explanation:

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3 5

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3 years ago

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Y_Kistochka [10]

Step-by-step explanation:

A fence for a rectangular garden with one side against an existing wall is constructed by using 60 feet of fencing.

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Let 'x' be the width of the wall

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Formula for the area of the rectangle is

$Area=length \cdot width\\A=length(x)$

Replace the length we got using perimeter

$A=(30-x)(x)\\A(x)= 30x-x^2$

To find out the maximum are we take derivative

$A'(x)= 30-2x\\0=30-2x\\-30=-2x\\x=15$

find out second derivative to check whether x=15 is maximum

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second derivative is negative

So, Maximum area at x=15

To find maximum area we plug in 15 for x in A(x)

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Answer:

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