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marusya05 [52]
3 years ago
6

5x^2-4x=6 solve for x

Mathematics
1 answer:
ikadub [295]3 years ago
8 0
Let's solve your equation step-by-step.<span><span><span><span>5x</span><span>(2)</span></span>−<span>4x</span></span>=6</span>Step 1: Simplify both sides of the equation.<span><span><span><span>5x</span><span>(2)</span></span>−<span>4x</span></span>=6</span><span>Simplify: (Show steps)</span><span><span><span><span>10x</span>+</span>−<span>4x</span></span>=6</span><span><span>(<span><span>10x</span>+<span>−<span>4x</span></span></span>)</span>=6</span>(Combine Like Terms)<span><span>6x</span>=6</span><span><span>6x</span>=6</span>Step 2: Divide both sides by 6.<span><span><span>‌<span><span>6x</span>6</span></span>‌</span>=<span><span>‌<span>66</span></span>‌</span></span><span>x=1</span>Answer:<span>x=<span>1</span></span>
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NikAS [45]

the departure time is 2:24 pm

8 0
3 years ago
What is the best approximation of the projection of (5,-1) onto (2,6)?
Hatshy [7]

Answer:

Hence, the scalar projection of \vec a onto \vec b= \frac{\sqrt{10} }{5}, and  the vector projection of \vec a onto \vec b = \frac{1}{5} \hat i+\frac{3}{5} \hat j.

Step-by-step explanation:

We have given two points  (5, -1) and (2, 6).

Let,     \vec a=5\hat {i}-\hat {j}  and  \vec b= 2\hat {i}+6\hat{j} .

and we have calculate the projection of \vec a onto \vec b.

Now,

For the calculation of projection, first we need to calculate the dot product of  \vec a  and \vec b.

\vec a.\vec b=(5\hat {i}-\hat{j}).(2\hat{i}+6\hat{j})

     =10-6

     =4

then, we have to calculate the magnitude of \vec b.

   \mid {\vec {b}}\mid = \sqrt{2^{2}+6^{2}  } = \sqrt{40} = 2\sqrt{10}.

Now, the scalar projection of \vec a onto \vec b = \frac{\vec a.\vec b}{\mid b\mid}

                                                                 = \frac{4}{2\sqrt{10} }\frac{2}{\sqrt{10} } \times\frac{\sqrt{10} }{\sqrt{10} } =\frac{2\sqrt{10} }{10} = \frac{\sqrt{10} }{5}

and the vector projection of \vec a onto \vec b = \frac{\vec a. \vec b}{\mid\vec b \mid^{2} } . \vec b

                                                               = \frac{4}{40} . (2\hat i+ 6\hat j)

                                                                = \frac{1}{5} \hat i+\frac{3}{5} \hat j

Hence, the scalar projection of \vec a onto \vec b= \frac{\sqrt{10} }{5}, and  the vector projection of \vec a onto \vec b = \frac{1}{5} \hat i+\frac{3}{5} \hat j.

                                                               

6 0
4 years ago
Solve the equation for all values of x by completing the square.<br> 3x^2-60x+255=0
erik [133]

Answer:

x=5 and x=15

Step-by-step explanation:

3x^2-60x+225=0

3x^2-60x+225/3=0/3

x^2-20x+75=0

x^2-5x-15x+75=0

x(x-5)-15(x-5)=0

(x-5)(x-15)=0

x-5=0 x-15=0

x=5 x=15

4 0
3 years ago
How do you convert this mixed fraction 8 21/40 into a decimal
Reika [66]
First u must make this mixed fraction to a fraction by multiplying 8 with 40 which equals to 320 then u add 320 with 21 which equals to 341:
341/40, well now this is an improper fraction. So now u will divide 341 by 40 and whatever u get is ur answer.
341÷40=8.525.
HOPE THIS HELPS AND IS NOT CONFUSING!!!!!! IF IT IS THEN COMMENT BELOW AND I WILL EXPLAIN EASIER.
5 0
3 years ago
What equation has the solution of -5 and 7
Sergio [31]

Answer:

x-2x-35

Step-by-step explanation:

-5 and 7

x=-5

x=7

x+5=0

x-7=0

Put them in bracket.

(x+5)(x-7)

Expanding the bracket

x(x-7)+5(x-7)

x-7x+5x-35

x-2x-35

7 0
3 years ago
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