3 years ago

Do you guys know how to do this I am struggling and need help?

Mathematics

1 answer:

Oksanka [162]3 years ago

3 0

Answer:

i think its 234

Step-by-step explanation:

You might be interested in

59 pounds to 35 pounds increase or decrease

frutty [35]

If you went from 59 pounds to 35 pounds, that's a 24 pound decrease.

4 0

3 years ago

⭐️⭐️ILL MAKE YOU BRAINLIEST⭐️⭐️ Simplify 4 — 1 — 5

Sonja [21]

Answer:

idk 3 maybeeed im in 3rd grade idk

5 0

4 years ago

Let f(x) = 3x - 7. What is f(1)?

Ipatiy [6.2K]

Answer:

negative 4 i think im dumb tho

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

maxonik [38]

Answer:

5.0 ft-lbf

Step-by-step explanation:

The force is

$F = \dfrac{9}{6^x}$

This force is not a constant force. For a non-constant force, the work done, W, is

$W = \int\limits^{x_2}_{x_1} {F(x)} \, dx$

with $x_1$ and $x_2$ the initial and final displacements respectively.

From the question, $x_1 =0$ and $x_2 = 12$ .

Then

$W = \int\limits^{12}_0 {\dfrac{9}{6^x}} \, dx$

Evaluating the indefinite integral,

$\int\limits \dfrac{9}{6^x} \, dx =9 \int\limits\!\left(\frac{1}{6}\right)^x \, dx$

From the rules of integration,

$\int\limits a^x\, dx = \dfrac{a^x}{\ln a}$

$9 \int\limits \left(\frac{1}{6}\right)^x \, dx = 9\times\dfrac{(1/6)^x}{\ln(1/6)} = -5.0229\left(\dfrac{1}{6}\right)^x$

Returning the limits,

$\left.-5.0229\left(\dfrac{1}{6}\right)^x\right|^{12}_0 = -5.0229(0.1667^{12} - 0.1667^0) = 5.0229 \approx 5.0 \text{ ft-lbf}$

4 0

4 years ago

I’m stuck on both I only have 5 minutes

Maslowich

Answer:

what are you looking for area or perimeter

6 0

3 years ago

Read 2 more answers