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Wittaler [7]
3 years ago
8

what is the equation that represents the sentence, twenty four is the sum of a number and six use x for the variable​

Mathematics
1 answer:
Rasek [7]3 years ago
4 0

Answer:

24 = x + 6

Step-by-step explanation:

24 =  x + 6

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Suppose a candy bar weighs 5.49 ounces. How much does a pack of 6 bars weigh?
s2008m [1.1K]

Answer:

32.94 ounces

if one candy bar is 5.49 ounces, and its asking for 6, multiply 5.49 by 6

5 0
3 years ago
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Factor
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(12x+13)2 hope this helps

7 0
3 years ago
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If the divisor is 40, what is the least three-digit dividend that would give a remainder of 4?
pantera1 [17]
Take 40 and multiply it by any number bigger than 2 then add 4.

124,164,204
4 0
3 years ago
Pls help with both 19 and 20 I’ll mark brainliest, show how you set up the problems
belka [17]
<h2>Answer:</h2>

<u>Question 19:</u>

Option A:

40 x 19 = 760

Option B:

A: 9,500 x 8 = 76,000

    76,000 ÷ 100 = 760

B: 4,750 x 8 = 38,000

   38,000 ÷ 100 = 380

C: 760 x 8 = 6,080

   6,080 ÷ 100 = 60.8

D: 320 x 8 = 2,560

   2,560 ÷ 100 = 25.6

<em>Answer:</em> $9,500

<u>Question 20:</u>

5.5 x 30 = 165

165 ÷ 100 = 1.65

1.65 + 5.5 = 7.15

Commission: 7.15%

382,000 x 7.15 = 2,731,300

2,731,300 ÷ 100 = 27,313

<em>Answer:</em> The agent earns $27,313 in commissions.

4 0
3 years ago
Log5(x-1)+log5(x+3)-1=0
jonny [76]

Answer:

there are no real solutions

Step-by-step explanation:

\log_5(x-1)+\log_5(x+3)-1=0\\\\\log_5(x-1)+\log_5(x+3)=1

there is a rule that says

\log_b(a)+\log_b(c)=\log_b(ac)

so we have

\log_5(x-1)+\log_5(x+3)=\log_5((x-1)(x+3))=1

and we have the definition

\log_a(b)=c\\\\a^{c} =b

so we have

5^{1} = (x-1)(x+3)\\\\5=x^{2} -1x+3x-3\\\\5=x^{2} +2x-3\\\\0=x^{2} +2x-3-5\\\\0=x^{2} +2x-8\\\\

and using the quadratic formula we get that

there are no real solutions

3 0
4 years ago
Read 2 more answers
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