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Ludmilka [50]
2 years ago
14

What will be the new position of the given point (-2,7)after translation of 3 units up and 1 units left?

Mathematics
1 answer:
Sindrei [870]2 years ago
5 0

Answer:( -3, 10)

Step-by-step explanation:

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Which rule describes the transformation that is a reflection across the x-acis
Alla [95]

Answer:

When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places. If you reflect over the line y = -x, the x-coordinate and y-coordinate change places and are negated (the signs are changed). the line y = x is the point (y, x). the line y = -x is the point (-y, -x).

7 0
3 years ago
Jake has two similar cylindrical pipes. The radius of the first cylindrical pipe is 5 cm. The circumference of the second cylind
Anna11 [10]
V=hpir^2
c=2pir

assuming they havve same height

first one is
v=hpi5^2
v=25hpi

2nd one
c=2pir=20pi
2pir=20pi
2r=20
r=10
v=hpir^2
v=hpi10^2
v=100hpi

big/small=100hpi/25hpir=4

4 times greater
4 0
3 years ago
What is the value of the following expression? <br> 7+18/(6-3)
daser333 [38]
7+18/(6-3)
7+18/3
25/3=8.333
5 0
3 years ago
For the line segment whose endpoints are A (0, 0) and B (4, 3), find the x coordinate for the point located 2 over 3 the distanc
WARRIOR [948]

Answer:

<h3>3.3</h3>

Step-by-step explanation:

Distance between AB is expressed as;

AB = √(3-0)²+(4-0)²

AB = √3²+4²

AB =√9+16

AB = √25

AB = 5

2 over 3 the distance from A to B is expressed as;

2/3 of AB

= 2/3 * 5

=10/3

= 3.3

6 0
3 years ago
Read 2 more answers
the endpoints of the diameter of a circle are (−6, 6) and (6, −2), what is the standard form equation of the circle?
miss Akunina [59]
The equation of a circle in standard form is

(x - h)^2 + (y - k)^2 = r^2

where (h, k) is the center of the circle, and r is the radius if the circle.

We need to find the radius and center of the circle.
We are given a diameter, so to find the center, we need the midpoint of the diameter.

M = ((-6 + 6)/2, (6 + (-2))/2) = (0, 2)
The center is (0, 2).

To find the radius, we find the length of the given diameter and divided by 2.

d = \sqrt{(-6 - 6)^2 + (6 - (-2))^2)}

d = \sqrt{144 + 64}

d = \sqrt{208}

r = \dfrac{d}{2} = \dfrac{\sqrt{208}}{2} = \dfrac{\sqrt{208}}{\sqrt{4}} = \sqrt{52}

(x - 0)^2 + (y - 2)^2 = (\sqrt{52})^2

x^2 + (y - 2)^2 = 52
7 0
3 years ago
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