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Ipatiy [6.2K]
3 years ago
10

Answere 4 and 6 PLEASE show work

Mathematics
1 answer:
max2010maxim [7]3 years ago
6 0
I think 4 is 3 pages plus 1/4=3 1/4

and 6 is 5+1/3= 5 1/3

hope this helpa
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4 0
3 years ago
Is 10/9 closest to 0, 1/2 or 1? <br> Explain<br><br> Is 2/15 closest to 0, 1/2 or 1?<br> Explain
const2013 [10]
10/9 can be rewritten as 1 1/9, so it's closest to 1. 2/15 is really small, so close to 0.
4 0
3 years ago
If 3612 – m – 62m, what is the value of m?<br> LEO<br> ООО<br> о со од
nasty-shy [4]

Answer:

3612 - 63 m

Step-by-step explanation:

3612 – m – 62m

We cannot find the value of m, but we can simplify the expression

3612 – m – 62m

3612 - 63 m

5 0
3 years ago
Elena bikes 20 minutes each day for exercise. Write an equation to describe the relationship between her distance in miles, D, a
kompoz [17]

<u>Answer:</u>

The equation to describe the relationship between Elena distance:

a) D = 4.34 miles, b) D = 4.25 miles and c) 12D = M + 3N miles.

<u>Solution:</u>

Given, Elena bikes 20 minutes each day for exercise.  

We have to write an equation to describe the relationship between her distance in miles, D, and her biking speed, in miles per hour,  

We know that, distance travelled = speed \times time

a. At a constant speed of 13 miles per hour for the entire 20 minutes  

Her speed is 13 miles per hour.  

Then, distance D miles = 13 miles per hour \times 20 minutes

\mathrm{D}=13 \text { miles per hour } \times \frac{20}{60} \text { hours } \rightarrow \mathrm{d}=13 \times \frac{1}{3} \rightarrow \mathrm{d}=4.34 \text { miles approximately. }

b. At a constant speed of 15 minutes per hour for the first 5 minutes, then at 12 miles per hour for the last 15 minutes  

Now, total distance travelled = distance travelled with 15 mph + distance travelled with 12 mph

\begin{array}{l}{\mathrm{D}=15 \mathrm{mph} \times 5 \text { minutes }+12 \mathrm{mph} \times 15 \text { minutes }} \\\\ {\mathrm{D}=15 \mathrm{mph} \times \frac{5}{60} \text { hours }+12 \mathrm{mph} \times \frac{15}{60} \text { minutes }} \\\\ {\mathrm{D}=15 \times \frac{1}{12}+12 \times \frac{1}{4} \rightarrow \mathrm{D}=\frac{5}{4}+3 \rightarrow \mathrm{D}=3+1.25 \rightarrow \mathrm{D}=4.25 \mathrm{miles}}\end{array}

c. At a constant speed of M miles per hour for the first 5 minutes, then at N miles per hour for the last 15 minutes

Now, total distance travelled = distance travelled with M mph + distance travelled with N mph

D = M mph \times 5 minutes + N mph \times 15 minutes

\mathrm{D}=\mathrm{M} \mathrm{mph} \times \frac{5}{60} \text { hours }+\mathrm{N} \mathrm{mph} \times \frac{15}{60} \text { minutes }

\mathrm{D}=\mathrm{M} \times \frac{1}{12}+\mathrm{N} \times \frac{1}{4} \rightarrow \mathrm{D}=\frac{M}{12}+\frac{N}{4} \rightarrow \mathrm{D}=\frac{M}{12}+\frac{3 N}{12} \rightarrow 12 \mathrm{D}=\mathrm{M}+3 \mathrm{N} \text { miles }

Hence, a) D = 4.34 miles, b) D = 4.25 miles and c) 12D = M + 3N miles.

8 0
4 years ago
What are the next 3 terms of this pattern? 4, 16, 64...
Lera25 [3.4K]

Answer:

256, 1024, 4096

Step-by-step explanation:

They multiply by four

pls mark me brainiest

5 0
3 years ago
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